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musickatia [10]
3 years ago
7

I need help is it A b C or D

Mathematics
2 answers:
mr_godi [17]3 years ago
7 0
The answer is C I think
kvv77 [185]3 years ago
3 0
I think the answer is C
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A hovercraft takes off from a platform. Its height (in meters), xxx seconds after takeoff, is modeled by: h(x)=-2x^2+20x+48h(x)=
Ad libitum [116K]

the maximum height is the y-value of the vertex.

h(x) = -2x² + 20x + 48

      <em>  a=-2, b=20, c=48</em>

x = \frac{-b}{2a} = \frac{-20}{2(-2)} = \frac{-20}{-4} = 5

h(5) = -2(5)² + 20(5) + 48

      =  -50   +  100   + 48

      =          50         + 48

      =                98

Answer: 98 meters

8 0
3 years ago
Which of the following linear inequalities matches the given graph below?
frozen [14]

Answer:

O y > 4

Step-by-step explanation:

The dotted line indicates the line is not part of the inequality, and it is clearly greater than 4.

8 0
2 years ago
Please help me, haha...
sashaice [31]
Yup the answer is C !!
3 0
3 years ago
Josephine noticed that out of 10 e-mails she received, 7 were advertisements. What can she predict about the number of advertise
andriy [413]
She can expect 70 to be ads since there is 10 times more emails so 7 times 10 is 70 so 70 ads
4 0
3 years ago
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In a​ study, 36​% of adults questioned reported that their health was excellent. A researcher wishes to study the health of peop
steposvetlana [31]

Answer:

0.3907

Step-by-step explanation:

We are given that 36​% of adults questioned reported that their health was excellent.

Probability of good health = 0.36

Among 11 adults randomly selected from this​ area, only 3 reported that their health was excellent.

Now we are supposed to find the probability that when 11 adults are randomly​ selected, 3 or fewer are in excellent health.

i.e. P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)

Formula :P(x=r)=^nC_r p^r q ^ {n-r}

p is the probability of success i.e. p = 0.36

q = probability of failure = 1- 0.36 = 0.64

n = 11

So, P(x\leq 3)=P(x=1)+{P(x=2)+P(x=3)

P(x\leq 3)=^{11}C_1 (0.36)^1 (0.64)^{11-1}+^{11}C_2 (0.36)^2 (0.64)^{11-2}+^{11}C_3 (0.36)^3 (0.64)^{11-3}

P(x\leq 3)=\frac{11!}{1!(11-1)!} (0.36)^1 (0.64)^{11-1}+\frac{11!}{2!(11-2)!}  (0.36)^2 (0.64)^{11-2}+\frac{11!}{3!(11-3)!} (0.36)^3 (0.64)^{11-3}

P(x\leq 3)=0.390748

Hence  the probability that when 11 adults are randomly​ selected, 3 or fewer are in excellent health is 0.3907

5 0
3 years ago
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