Look at the PDF and look answer the question, pls do explain

Mathematics

2 answers:

gulaghasi [49]3 years ago

8 0

Answer:

26 hamburgers.

Step-by-step explanation:

8 2/3=26/3 each hamburger takes 1/3 meat. So 26/3 ÷1/3=26

luda_lava [24]3 years ago

8 0

Answer:

26 hamburgers can be made

Step-by-step explanation:

Below is my work, but I'll explain here.

1) make an equation. We know the total is $8\frac{2}{3}$ pounds and each hamburger requires $\frac{1}{3}$ pounds.

2) make the fractions easy to read. turn the $8\frac{2}{3}$ into $\frac{26}{3}$ by multiplying 8 and 3 then adding 2 to the product.

3) Solve for x! Once you have $\frac{1}{3} x = \frac{26}{3}$ , divide $\frac{26}{3}$ by $\frac{1}{3}$ . You should get 26.

4) (optional) check your work by multiplying $\frac{1}{3}$ with 26. You should get $\frac{26}{3}$ .

**Hope this helps!

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The mayor is interested in finding a 98% confidence interval for the mean number of pounds of trash per person per week that is

saul85 [17]

Solution :

Given :

Sample mean, $\overline X = 34.2$

Sample size, n = 129

Sample standard deviation, s = 8.2

a. Since the population standard deviation is unknown, therefore, we use the t-distribution.

b. Now for 95% confidence level,

α = 0.05, α/2 = 0.025

From the t tables, T.INV.2T(α, degree of freedom), we find the t value as

t =T.INV.2T(0.05, 128) = 2.34

Taking the positive value of t, we get

Confidence interval is ,

$\overline X \pm t \times \frac{s}{\sqrt n}$

$34.2 \pm 2.34 \times \frac{8.2}{\sqrt {129}}$

(32.52, 35.8)

95% confidence interval is (32.52, 35.8)

So with $95 \%$ confidence of the population of the mean number of the pounds per person per week is between 32.52 pounds and 35.8 pounds.

c. About $95 \%$ of confidence intervals which contains the true population of mean number of the pounds of the trash that is generated per person per week and about $5 \%$ that doe not contain the true population of mean number of the pounds of trashes generated by per person per week.