Answer:
Power generated = 4.315 kW
Step-by-step explanation:
Given,
- speed of wind when enters into the turbine, V = 12 m/s
- speed of wind when exits from the turbine, U = 9 m/s
- mass flow rate of the wind, m = 137 kg/s
According to the law of conservation of energy
Energy generated = change in kinetic energy
Since, the air is exiting at same elevation. So, we will consider only kinetic energy.
Energy generated in one second will be given by,
=4315.5 J
= 4.315 kJ
So, energy is generated in one second = 4.315 kJ
Power generated can be given by,
And the energy is generated is already in per second so power generated will be 4.315 kW.
Answer:
21
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Step-by-step explanation:
<u>Step 1: Define expression</u>
3 × 3 + 3 + 3 × 3
<u>Step 2: Evaluate</u>
- Multiply: 9 + 3 + 3 × 3
- Multiply: 9 + 3 + 9
- Add: 12 + 9
- Add: 21
Answer:
A
Step-by-step explanation:
(4q-6n) /(3m) =f
4q-6n=f(3m)
4q=3fm+6n
q=(3fm+6n)/4