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andrezito [222]
3 years ago
12

System of equations, 3x - 6y =2 5x + 4y = 1

Mathematics
1 answer:
Anettt [7]3 years ago
7 0
3x-6y=2 (label equation 1)
5x+4y=1 (label equation 2)
-6y=-3x+2 (rearranged equation 1)
y=1/2x-1/3 (label equation 3)
 substitute equation 3 into equation 2 
5x+4(1/2x-1/3)=1
5x+2x-4/3=1
15x+6x-4=3 (multiplied everything by 3)

21x-4=3
     +4  +4
21x=7
x= 7/21
x=1/3

sub x=7/21 into equation 3
y= 1/2(1/3) -1/3
y= -1/6


Therefore x=1/3 and y= -1/6



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r^3=\dfrac{\frac{63}{8}}{\frac{7}{3}}\\\\r^3=\dfrac{63}{8}\cdot\dfrac{3}{7}\\\\r^3=\dfrac{9\cdot3}{8\cdot1}\\\\r^3=\dfrac{27}{8}\to r=\sqrt[3]{\dfrac{27}{8}}\\\\r=\dfrac{3}{2}\\\\h=2\dfrac{1}{3}\cdot\dfrac{3}{2}=\dfrac{7}{3}\cdot\dfrac{3}{2}=\dfrac{7}{2}\\\\k=\dfrac{7}{2}\cdot\dfrac{3}{2}=\dfrac{21}{4}\\\\Answer:\ \boxed{h=\dfrac{7}{2}=3\dfrac{1}{2}\ and\ k=\dfrac{21}{4}=5\dfrac{1}{4}}

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Bonnie is making a dipping sauce. She mixes 150 milliliters of soy sauce with 100 milliliters of vinegar. How much soy sauce doe
oksian1 [2.3K]

Answer:

Bonnie is mixing 1.50 milliliter of soy sauce with 1 milliliter of vinegar

Step-by-step explanation:

Given

Bonnie mixes 150 milliliters of soy sauce with 100 milliliters of vinegar

So, in order to find the amount of soy sauce mixed with one ml of vinegar, we have to divide the amount of soy sauce by vinegar.

So,

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Answer:

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