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sveta [45]
3 years ago
11

Simplify.

3]{8m} {}^{3} " alt=" \sqrt[3]{8m} {}^{3} " align="absmiddle" class="latex-formula">
Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
7 0

\sqrt[3]{8m}^3

  • Set up

(8m^{\frac{1}{3}})^3

  • Convert the radical into a fractional exponent using \sqrt[n]{x^m} = x^{\frac{m}{n}}

8m^{(3 \cdot \frac{1}{3})}

  • Use the property that (x^a)^b = x^{(a \cdot b)}

8m

  • Simplify

The simplification would be 8m.



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I need help with this one plz! (marking BRAINLIST) :) ​
miskamm [114]

Answer: (a) = 110 degrees, (b) = 8

If I understand the picture correctly, (a) wants you to find the angle K. It first shows us that both J to K, and L to K are equal in length of 11, thus there is no deviation in angle 35 degrees with L (so they both equal each other). Therefore, the angle K will equal 180 degrees subtracted by the sum of J and L, which is 110 degrees.

For (b), it appears that all the angles have the same singular mark at the edges, so all sides will equal 8.

I hope this helped!

3 0
2 years ago
Eight more than the product of a number and 4 is 9 . Use the variable w for the unknown number.
Stolb23 [73]
9* (w+8)=4 is the equation
8 0
3 years ago
Read 2 more answers
Find ,H assuming the triangles formed are similar.
Murljashka [212]

Answer:

15

Step-by-step explanation:

if you divide 20 by 8, then you get 2.5. multiply that by six, and you get your answer.

6 0
3 years ago
Some transportation experts claim that it is the variability of speeds, rather than the level of speeds, that is a critical fact
scZoUnD [109]

Answer:

Explained below.

Step-by-step explanation:

The claim made by an expert is that driving conditions are dangerous if the variance of speeds exceeds 75 (mph)².

(1)

The hypothesis for both the test can be defined as:

<em>H</em>₀: The variance of speeds does not exceeds 75 (mph)², i.e. <em>σ</em>² ≤ 75.

<em>Hₐ</em>: The variance of speeds exceeds 75 (mph)², i.e. <em>σ</em>² > 75.

(2)

A Chi-square test will be used to perform the test.

The significance level of the test is, <em>α</em> = 0.05.

The degrees of freedom of the test is,

df = n - 1 = 55 - 1 = 54

Compute the critical value as follows:

\chi^{2}_{\alpha, (n-1)}=\chi^{2}_{0.05, 54}=72.153

Decision rule:

If the test statistic value is more than the critical value then the null hypothesis will be rejected and vice-versa.

(3)

Compute the test statistic as follows:

\chi^{2}=\frac{(n-1)\times s^{2}}{\sigma^{2}}

    =\frac{(55-1)\times 94.7}{75}\\\\=68.184

The test statistic value is, 68.184.

Decision:

cal.\chi^{2}=68.184

The null hypothesis will not be rejected at 5% level of significance.

Conclusion:

The variance of speeds does not exceeds 75 (mph)². Thus, concluding that driving conditions are not dangerous on this highway.

7 0
3 years ago
Answer questions (a-d) for the following three data sets.
GrogVix [38]
The mean is
A. 8.4
B.5.2
C.9.4
6 0
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