1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
shutvik [7]
3 years ago
14

alt=" \frac{y}{2} < - 3" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Allisa [31]3 years ago
8 0
Hey!


Okay, to solve this problem, we'd first have to multiply both sides by two. The reason we do this is to get y on its own.

<em>Original Equation : </em>
\frac{y}{2} < -3

<em>New Equation {Changed by Multiplying 2 on Both Sides} :</em>
\frac{2y}{2} < 2 ( -3 )

And we simplify the equation to get our answer.

<em>Old Equation :</em>
\frac{2y}{2} < 2 ( -3 )

<em>New Equation {Changed by Simplification} :</em>
y < -6

<em>So, the equation \frac{y}{2} < -3 simplified is</em>  y < -6.

Hope this helps!


- Lindsey Frazier ♥
You might be interested in
How can we describe the relationships that exist between circles and lines?
Lunna [17]

circles are 360⁰ and lines are 180⁰

5 0
2 years ago
Solve x^2 - 3x - 10 = 0
Pachacha [2.7K]

Answer:

5 and -2

Step-by-step explanation:

{x}^{2}  - 3x - 10 = 0

{x}^{2}  - 5x + 2x - 10 = 0

x(x - 5) + 2(x - 5) = 0

(x - 5)(x + 2) = 0

x - 5 = 0

x = 5

or

x + 2 = 0

x =  - 2

6 0
2 years ago
Please help me with this MATH question.
olasank [31]

Answer:

Step-by-step explanation:

41

6 0
3 years ago
Read 2 more answers
if in the study of the lifetime of 60-watt light bulbs it was desired to have a margin of error no larger than 6 hours with 99%
Dahasolnce [82]

The question is incomplete! Complete question along with answer and step by step explanation is provided below.

Question:

The lifetime (in hours) of a 60-watt light bulb is a random variable that has a Normal distribution with σ = 30 hours. A random sample of 25 bulbs put on test produced a sample mean lifetime of = 1038 hours.

If in the study of the lifetime of 60-watt light bulbs it was desired to have a margin of error no larger than 6 hours with 99% confidence, how many randomly selected 60-watt light bulbs should be tested to achieve this result?

Given Information:

standard deviation = σ = 30 hours

confidence level = 99%

Margin of error = 6 hours

Required Information:

sample size = n = ?

Answer:

sample size = n ≈ 165

Step-by-step explanation:

We know that margin of error is given by

Margin of error = z*(σ/√n)

Where z is the corresponding confidence level score, σ is the standard deviation and n is the sample size

√n = z*σ/Margin of error

squaring both sides

n = (z*σ/Margin of error)²

For 99% confidence level the z-score is 2.576

n = (2.576*30/6)²

n = 164.73

since number of bulbs cannot be in fraction so rounding off yields

n ≈ 165

Therefore, a sample size of 165 bulbs is needed to ensure a margin of error not greater than 6 hours.

3 0
3 years ago
За – 15b – 2c|<br> HELPPP!!
nekit [7.7K]

Answer:

what are solving it with??

7 0
3 years ago
Other questions:
  • the price of a dress is 95.95 the state sales tax is 8.75% added then a 10.50 charge for shipping was added after the sales tax
    9·2 answers
  • Please help me in the question above? Please!!
    10·1 answer
  • Use the model to solve for x <br><br>A) X=2<br>B) X=4<br>C) X=8<br>D) X=12 ​
    7·2 answers
  • What is c=2πr solve for c
    6·2 answers
  • The rectangle below has a area of 160in2 find the one that is Not true
    6·1 answer
  • 7. Consider the inequality below. PART A: Select all values of x that make the inequality true. *
    7·1 answer
  • Find COS Instructions: Find the value of the trigonometric ratio. Make sure to simplify the If needed
    12·1 answer
  • Which line is the graph of y= 1/2 x + 1?
    8·2 answers
  • Help please ?!?!?!!???????!???!???!!????!!??!??!?!?!!??!?!!????
    9·1 answer
  • What is the average rate of change for this quadratic function for the interval fr x=2 to x=4?
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!