Lauren is shopping and finds 6 bracelets, 2 pairs of earrings, and 3 necklaces that she likes. How many ways can Lauren select 4
2 answers:
Because it does not specify that she has to choose one or two from each category all pieces of jewelry can be treated as choices in a combination set.
the formula for a combination is
where n is a total number of choices ( 11 )
and r is number chosen out of those choices (4)
so
C(11,4)= \frac{11!}{4!(11-4)!}
She has 330 possible choices to come home with 4 pieces of jewelry
the formula for a combination is
where n is a total number of choices ( 11 )
and r is number chosen out of those choices (4)
so
C(11,4)= \frac{11!}{4!(11-4)!}
She has 330 possible choices to come home with 4 pieces of jewelry
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<h2>Answer :-</h2>
As we know that,
Pythagoras triplet
1) a² + b² = c²
Let
- 8 ≠ 16
2) a² + b² = c²
- 169 = 169
3)a² + b² = c²
- 34 ≠ 36
4) a² + b² = c²
- 41 ≠ 49
Only B can be Pythagoras triplet.