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leva [86]
3 years ago
13

Custumers of a phone company can choose between two service plans for long distance calls. The first plan has a $9 monthly fee a

nd charges an aditional $0.13 for each minute pf calls. The second plan has $23 monthly fee and charges an additional $0.09 monthly for each minute of calls. For how many minutes of calls will the costs of the two plans be equal
Mathematics
2 answers:
Zinaida [17]3 years ago
5 0
9+0.13x
23+0.09x
im not sure if thats how u solve it but i tried my best to help sorry
saul85 [17]3 years ago
3 0
The answer is 350.
<em>
m= minutes</em>

Plan 1:  9+0.13<em>m</em>
Plan 2:  23+0.09<em>m</em>

9+0.13<em>m</em> = 23+0.09<em>m</em>
-9               -9
0.13<em>m</em> = 14+0.09<em>m</em>
-0.09<em>m</em>        -0.09<em>m</em>
0.04<em>m</em>= 14
14÷0.04= 350
<em>m</em>= 350
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Answer:

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Step-by-step explanation:

For any function to be defined at a particular value, it should not be <em>approaching to a value </em>\infty<em> or it should not give us the </em>\frac{0}{0}<em> (zero by zero) form </em> when the input is given to the function.

The value of function will depend on the denominator.

Now, let us consider the given functions one by one:

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Here denominator is 1. So, it can not attain a value \infty or \frac{0}{0}<em> (zero by zero) form </em>

So, for all real numbers, the function is defined.

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At y = 0, the value

At\ y =0,  \dfrac{18}{y} \rightarrow \infty

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x + 7 can be zero at a value x = -7

At\ x =-7,  \dfrac{1}{x+7} \rightarrow \infty

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4.\ \dfrac{2b}{10-b}

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10-b can be zero at a value b = 10

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3 years ago
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Answer:

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for b

b) {(1, 1), (1, 4), (2, 2), (3, 3), (4, 1)}

\left[\begin{array}{cccc}1&0&0&1\\0&1&0&0\\0&0&1&0\\1&0&0&0\end{array}\right]

for c) {(1, 2), (1, 3), (1, 4), (2, 1), (2, 3), (2, 4), (3, 1), (3, 2), (3, 4), (4, 1), (4, 2), (4, 3)}

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Step-by-step explanation:

in matrix, arrays are placed in rows , which represents the horizontal sides from left to right, while arrays in the column are placed vertically from top to bottom. Here, we placed the arrays in a 4x4 matrix

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\left[\begin{array}{cccc}0&1&1&1\\0&0&1&1\\0&0&0&1\\0&0&0&0\end{array}\right]

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