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4 years ago

Simplify the expression: (-3x - 8)(-x+4)

Mathematics

2 answers:

SashulF [63]4 years ago

4 0

Answer:3

Step-by-step explanation:

torisob [31]4 years ago

3 0

Answer:

3x^2 - 5x - 32

Step-by-step explanation:

FOIL this!

(-3x * -x)-13x+8x-32

3x^2-5x-32

watch the signs.

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55 men can finish a piece of work in 42 days. How many additional men must be added to complete the work 9 days earlier.

Alisiya [41]

$55 . 42 = x . 33\\55 . 14 = 11 . x\\x = 5 . 14 = 70\\70 - 55 = 15$ Answer:

Step-by-step explanation:

6 0

4 years ago

Cynthia invests some money in a bank which pays

USPshnik [31]

Let ,Cynthia invested $x

Rate = 5%per year

time = 3 year

Amount

A= P(1+r/100)^t

8000=x(1+5/100)^3

8000=x(21/20)^3

x= (8000x8000)/9261

x=6910.7$

Therefore she can invest =$6910.7 =5322.14 pound

4 0

3 years ago

3 times the difference between 41 and 30

Katen [24]

Answer:

the answer would be 33.....

3 0

3 years ago

A certain type of automobile battery is known to last an average of 1140 days with a standard deviation of 80 days. If 400 of th

Sever21 [200]

Answer:

Mean = $\mu = 1140$

Standard deviation = $\sigma = 80$

Find the probabilities for the average length of life of the selected batteries.

A)The average is between 1128 and 1140.

We are supposed to fidn P(1128<x<1140)

Formula : $Z=\frac{x-\mu}{\sigma}$

At x = 1128

$Z=\frac{1128-1140}{80}$

$Z=-0.15$

Refer the z table for p value

P(x<1128)=0.4404

At x = 1140

$Z=\frac{1140-1140}{80}$

$Z=0$

Refer the z table for p value

P(x<1140)=0.5

So,P(1128<x<1140)=P(x<1140)-P(x<1128)=0.5-0.4404=0.0596

Hence the probabilities for the average length of life of the selected batteries is between 1128 and 1140 is 0.0596

B)The average is greater than 1152.

P(x>1152)

At x = 1128

$Z=\frac{1152-1140}{80}$

$Z=0.15$

Refer the z table for p value

P(x<1152)=0.5596

So,P(x>1152)=1-P(x<1152)=1-0.5596=0.4404

Hence the probabilities for the average length of life of the selected batteries is greater than 1152 is 0.4404

C) The average is less than 940.

P(x<940)

At x = 940

$Z=\frac{940-1140}{80}$

$Z=-2.5$

Refer the z table for p value

P(x<940)=0.5596

Hence the probabilities for the average length of life of the selected batteries is less than 940 is 0.5596

7 0

3 years ago

Six more than twice a number is 20

4vir4ik [10]

Answer:

Step-by-step explanation:

7x2=14

14+6=20

5 0

3 years ago