All categories

3 years ago

Can someone help me please

Mathematics

1 answer:

Tomtit [17]3 years ago

6 0

It would affect the mean the most

You might be interested in

What are 2 ways to find out if a couple planning on having 3 children, WON'T have any boys?

expeople1 [14]

is why the heck what is weird lol

7 0

3 years ago

I need help with question 1 URGENTTTTTT

Kamila [148]

When finding the area of a triangle, you always divide the product by 2 because a triangle is half a square.

7 0

4 years ago

Read 2 more answers

Suppose that college faculty with the rank of professor at two year institutions earn an average of $52,500 per year with a stan

icang [17]

Let x be a random variable representing the mean saraly of professors at two year institutions, then
P(x > 55000) = 1 - P(z < (55000 - 52500)/4000) = 1 - P(z < 0.625) = 1 - 0.73401 = 0.26599

8 0

3 years ago

Complete the simpliflication:<br> please help giving brainlest

Allushta [10]

Answer:

Step-by-step explanation:

4 0

2 years ago

Find the exact values of a) sec of theta b)tan of theta if cos of theta= -4/5 and sin<0

Gre4nikov [31]

Answer:

Using trigonometric ratio:

$\sec \theta = \frac{1}{\cos \theta}$

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

From the given statement:

$\cos \theta = -\frac{4}{5}$ and sin < 0

⇒ $\theta$ lies in the 3rd quadrant.

then;

$\sec \theta = \frac{1}{-\frac{4}{5}} = -\frac{5}{4}$

Using trigonometry identities:

$\sin \theta = \pm \sqrt{1-\cos^2 \theta}$

Substitute the given values we have;

$\sin \theta = \pm\sqrt{1-(\frac{-4}{5})^2 } =\pm\sqrt{1-\frac{16}{25}} =\pm\sqrt{\frac{25-16}{25}} =\pm \sqrt{\frac{9}{25} } = \pm\frac{3}{5}$

Since, sin < 0

⇒ $\sin \theta = -\frac{3}{5}$

now, find $\tan \theta$ :

$\tan \theta = \frac{\sin \theta}{\cos \theta}$

Substitute the given values we have;

$\tan \theta = \frac{-\frac{3}{5} }{-\frac{4}{5} } = \frac{3}{5}\times \frac{5}{4} = \frac{3}{4}$

Therefore, the exact value of:

(a)

$\sec \theta =-\frac{5}{4}$

(b)

$\tan \theta= \frac{3}{4}$

7 0

4 years ago