What is less than 1/2 but greater than 2/8

Puteti sa ma ajutati va rog? Vreau solutii cu explicatie elaborata, nu doar raspunsul. Multumesc.

almond37 [142]

I don’t speak Spanish but if you put the English trans in the comments I’d love to answer

6 0

3 years ago

How do you graph? <br> y=−4/3x+8y

trasher [3.6K]

How do we graph anything? Make a table of values for x and y and then plot each point. After plotting each point on the xy-plane, connect each point with a straight line or curve (depending on the function).

In this case, we must first isolate y.

y = (-4/3)x + 8y

y - 8y = (-4/3)x

-7y = (-4/3)x

y = (-4/3)x ÷ (-7)

y = (4/21)x

Now follow the steps above.

8 0

3 years ago

Hamish rides his bike at an average speed of 22 km/h. How far does he ride in:

Andrej [43]

1=55 km
2=16.5km
3=5.5km

5 0

3 years ago

Read 2 more answers

Simplify x²-49/3x+21

Vera_Pavlovna [14]

First, you factor and simplify (respectively) the numerator and denominator. Your equation becomes:

$\frac{(x-7)(x+7)}{3(x + 7)}$

Notice, there is a (x + 7) on both the top and the bottom. Because of this, they cancel each other out. What is left is your answer:

$\frac{(x-7)}{3}$

3 0

3 years ago

Read 2 more answers

A teacher teaches two classes with 8 students each. Each student has a 95% chance of passing their class independent of the othe

dsp73

Answer:

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

Step-by-step explanation:

For each student, there are only two possible outcomes. Either they pass, or they do not. The probability of an student passing is independent of other students, which means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Probability that all students pass in a class:

Class of 8 students, which means that $n = 8$

Each student has a 95% chance of passing their class independent of the other students, which means that $p = 0.95$

This probability is P(X = 8). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{8,8}.(0.95)^{8}.(0.05)^{0} = 0.6634$

Find the probability that, in exactly one of the two classes, all 8 students pass.

Two classes means that $n = 2$

0.6634 probability all students pass in a class, which means that $p = 0.6634$ .

This probability is P(X = 1). So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 2) = C_{2,1}.(0.6634)^{1}.(0.3366)^{1} = 0.4466$

0.4466 = 44.66% probability that, in exactly one of the two classes, all 8 students pass.

3 0

3 years ago