Answer:
The smallest diameter of wrapper that will fit the candy bar is 6 cm
Step-by-step explanation:
The smallest diameter of the wrapper will have to be the length of the line AC.
We can observe that there are two similar triangles present in the shape there.
We have triangle ADE and triangle DCF
They are similar because their left side, base length, and right angle are equal.
We are given the length of the side AD for triangle ADE.
From the rules of similar triangles, we have that side DC will also equal 3 cm. because the two triangles are similar.
Hence AC will be 3cm + 3cm = 6 cm
The smallest diameter of wrapper that will fit the candy bar is 6 cm
Answer:
The prove is as given below
Step-by-step explanation:
Suppose there are only finitely many primes of the form 4k + 3, say {p1, . . . , pk}. Let P denote their product.
Suppose k is even. Then P ≅ 3^k (mod 4) = 9^k/2 (mod 4) = 1 (mod 4).
ThenP + 2 ≅3 (mod 4), has to have a prime factor of the form 4k + 3. But pₓ≠P + 2 for all 1 ≤ i ≤ k as pₓ| P and pₓ≠2. This is a contradiction.
Suppose k is odd. Then P ≅ 3^k (mod 4) = 9^k/2 (mod 4) = 1 (mod 4).
Then P + 4 ≅3 (mod 4), has to have a prime factor of the form 4k + 3. But pₓ≠P + 4 for all 1 ≤ i ≤ k as pₓ| P and pₓ≠4. This is a contradiction.
So this indicates that there are infinite prime numbers of the form 4k+3.
Answer: B. 30
Step-by-step explanation:
First, you re-write the expression
6(-3.5) + 15(4) - 12(3/4)
Then multiply all the parts correctly.
-21 + 60 - 9
-21 + 60 = 39
-9
= 30
Answer:
B and C
Step-by-step explanation:
Linear functions are written in the format y=mx+b
If a function has an exponent it is nonlinear
as the function is polynomial domain exist for all real number ie (-infinity to + infinity) but range exist (0 to +infinity ) due to modulus negetive range do not exist
