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Nataly [62]
3 years ago
9

Using the triangle pictured, find the measure of side AB. Round your answer to the nearest tenth. A) 1.6 B) 2.2 C) 2.7 D) 3.3

Mathematics
1 answer:
Yuki888 [10]3 years ago
6 0

Answer:

Option B (AB = 2.2 units).

Step-by-step explanation:

The diagram shows that there are two sides given and one angle is given. Therefore, the sine rule must be used to solve the question. The sine rule can be written as:

sin ABC / AC = sin BAC / BC.

Plugging ABC=72 degrees, AC=2.5, and BC=2.1 in the sine rule gives:

sin 72 / 2.5 = sin BAC / 2.1.

Cross multiplying gives:

sin BAC = (2.1*sin 72)/2.5.

sin BAC = 0.79888747368.

Taking sin inverse on both sides gives:

BAC = arcsin (0.79888747368) = 53.0239949 degrees.

To find AB, first, the angle ACB is required. To find that angle, use the triangular law of angles. All the three angles sum up to 180 degrees. Therefore ACB = 180 - 72 - 53.0239949 = 54.9760051  degrees.

Now applying the Sine Rule to find AB:

sin ACB / AB = sin ABC / AC.

sin (54.9760051) / AB = sin 72 / 2.5.

AB = (2.5*sin (54.9760051))/sin (72) = 2.2 (to the nearest tenth).

Therefore, AB = 2.2 units, i.e. Option B!!!

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I hope it's right :)

4 0
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Read 2 more answers
For the love of God help me !! I'm desperate for it tomorrow
Eduardwww [97]
Try to relax.  Your desperation has surely progressed to the point where
you're unable to think clearly, and to agonize over it any further would only
cause you more pain and frustration.
I've never seen this kind of problem before.  But I arrived here in a calm state,
having just finished my dinner and spent a few minutes rubbing my dogs, and
I believe I've been able to crack the case.

Consider this:  (2)^a negative power = (1/2)^the same power but positive.

So: 
Whatever power (2) must be raised to, in order to reach some number 'N',
the same number 'N' can be reached by raising (1/2) to the same power
but negative.

What I just said in that paragraph was:  log₂ of(N) = <em>- </em>log(base 1/2) of (N) .
I think that's the big breakthrough here.
The rest is just turning the crank.

Now let's look at the problem:

log₂(x-1) + log(base 1/2) (x-2) = log₂(x)

Subtract  log₂(x)  from each side: 

log₂(x-1) - log₂(x) + log(base 1/2) (x-2) = 0

Subtract  log(base 1/2) (x-2)  from each side:

log₂(x-1) - log₂(x)  =  - log(base 1/2) (x-2)  Notice the negative on the right.

The left side is the same as  log₂[ (x-1)/x  ]

==> The right side is the same as  +log₂(x-2)

Now you have:  log₂[ (x-1)/x  ]  =  +log₂(x-2)

And that ugly [ log to the base of 1/2 ] is gone.

Take the antilog of each side:

(x-1)/x = x-2

Multiply each side by 'x' :  x - 1 = x² - 2x

Subtract (x-1) from each side:

x² - 2x - (x-1) = 0

x² - 3x + 1 = 0

Using the quadratic equation, the solutions to that are
x = 2.618
and
x = 0.382 .

I think you have to say that <em>x=2.618</em> is the solution to the original
log problem, and 0.382 has to be discarded, because there's an
(x-2) in the original problem, and (0.382 - 2) is negative, and
there's no such thing as the log of a negative number.


There,now.  Doesn't that feel better. 
 






4 0
3 years ago
Plz help ill give 15 points
yan [13]

Answer:

b

Step-by-step explanation:

5 0
2 years ago
I need help ASAP!!!please help
muminat
Use 6 triangles then 2 square so you will only be using a total of 4 square and 12 triangles
8 0
3 years ago
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