What’s the least common multiple of three fiveand seven

The cost of 9 scarves is $83.25. What is the unit price?

melisa1 [442]

Answer:

9.25

Step-by-step explanation:

It's pretty simple all you have to do is 83.25 divided by 9.

7 0

3 years ago

Solve for F ------- 2/3 + f = 1/5 A= 13/15 B= 7/15 C= - !3/15 D= - 7/15

nikdorinn [45]

$\\ \sf\longmapsto \dfrac{2}{3}+f=\dfrac{1}{5}$

$\\ \sf\longmapsto f=\dfrac{1}{5}-\dfrac{2}{3}$

$\\ \sf\longmapsto f=\dfrac{3-10}{15}$

$\\ \sf\longmapsto f=\dfrac{-7}{15}$

8 0

3 years ago

Read 2 more answers

A sample of bacteria is growing at an hourly rate of 14% according to the exponential growth function. The sample began with 7 b

tatiyna

Answer:

125

Step-by-step explanation:

x(t) = x0 × (1 + r) t

where:

x(t) = the amount of some quantity at time t

x0 = initial amount at time t = 22

r = the growth rate

t = time

3 0

4 years ago

7x/3+2=-15 solve please!

marta [7]

How to solve your problem

Topics: Algebra, Polynomial

7

3

+

2

=

−

1

\frac{7x}{3}+2=-1

37x+2=−1

Solve

1

Find common denominator

7

3

+

2

=

−

1

\frac{7x}{3}+2=-1

37x+2=−1

7

3

+

3

⋅

2

3

=

−

1

\frac{7x}{3}+\frac{3 \cdot 2}{3}=-1

37x+33⋅2=−1

2

Combine fractions with common denominator

7

3

+

3

⋅

2

3

=

−

1

\frac{7x}{3}+\frac{3 \cdot 2}{3}=-1

37x+33⋅2=−1

7

+

3

⋅

2

3

=

−

1

\frac{7x+3 \cdot 2}{3}=-1

37x+3⋅2=−1

3

Multiply the numbers

7

+

3

⋅

2

3

=

−

1

\frac{7x+{\color{#c92786}{3}} \cdot {\color{#c92786}{2}}}{3}=-1

37x+3⋅2=−1

7

+

6

3

=

−

1

\frac{7x+{\color{#c92786}{6}}}{3}=-1

37x+6=−1

4

Multiply all terms by the same value to eliminate fraction denominators

7

+

6

3

=

−

1

\frac{7x+6}{3}=-1

37x+6=−1

3

(

7

+

6

3

)

=

3

(

−

1

)

3(\frac{7x+6}{3})=3\left(-1\right)

3(37x+6)=3(−1)

5

Cancel multiplied terms that are in the denominator

3

(

7

+

6

3

)

=

3

(

−

1

)

3(\frac{7x+6}{3})=3\left(-1\right)

3(37x+6)=3(−1)

7

+

6

=

3

(

−

1

)

7x+6=3\left(-1\right)

7x+6=3(−1)

6

Multiply the numbers

7

+

6

=

3

(

−

1

)

7x+6={\color{#c92786}{3}}\left({\color{#c92786}{-1}}\right)

7x+6=3(−1)

7

+

6

=

−

3

7x+6={\color{#c92786}{-3}}

7x+6=−3

7

Subtract

6

from both sides of the equation

7

+

6

=

−

3

7x+6=-3

7x+6=−3

7

+

6

−

6

=

−

3

−

6

7x+6{\color{#c92786}{-6}}=-3{\color{#c92786}{-6}}

7x+6−6=−3−6

8

Simplify

Subtract the numbers

7

=

−

9

7x=-9

7x=−9

9

Divide both sides of the equation by the same term

7

=

−

9

7x=-9

7x=−9

7

=

−

9

7

\frac{7x}{{\color{#c92786}{7}}}=\frac{-9}{{\color{#c92786}{7}}}

77x=7−9

10

Simplify

Cancel terms that are in both the numerator and denominator

=

−

9

7

x=\frac{-9}{7}

x=7−9

Solution

=

−

9

7

4 0

3 years ago

Find y' if y= In (x2 +6)^3/2 y'=

Schach [20]

Answer:

$\displaystyle y' = \frac{3xln(x^2 + 6)^{\frac{1}{2}}}{x^2 + 6}$

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets
Parenthesis
Exponents
Multiplication
Division
Addition
Subtraction

Left to Right

Algebra I

Factoring

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Derivative Property [Multiplied Constant]: $\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)$

Derivative Rule [Chain Rule]: $\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)$

ln Derivative: $\displaystyle \frac{d}{dx} [lnu] = \frac{u'}{u}$

Step-by-step explanation:

Step 1: Define

$\displaystyle y = ln(x^2 + 6)^{\frac{3}{2}}$

Step 2: Differentiate

[Derivative] Chain Rule: $\displaystyle y' = \frac{d}{dx}[ln(x^2 + 6)^{\frac{3}{2}}] \cdot \frac{d}{dx}[ln(x^2 + 6)] \cdot \frac{d}{dx}[x^2 + 6]$
[Derivative] Chain Rule [Basic Power Rule]: $\displaystyle y' = \frac{3}{2}ln(x^2 + 6)^{\frac{3}{2} - 1} \cdot \frac{d}{dx}[ln(x^2 + 6)] \cdot \frac{d}{dx}[x^2 + 6]$
[Derivative] Simplify: $\displaystyle y' = \frac{3}{2}ln(x^2 + 6)^{\frac{1}{2}} \cdot \frac{d}{dx}[ln(x^2 + 6)] \cdot \frac{d}{dx}[x^2 + 6]$
[Derivative] ln Derivative: $\displaystyle y' = \frac{3}{2}ln(x^2 + 6)^{\frac{1}{2}} \cdot \frac{1}{x^2 + 6} \cdot \frac{d}{dx}[x^2 + 6]$
[Derivative] Basic Power Rule: $\displaystyle y' = \frac{3}{2}ln(x^2 + 6)^{\frac{1}{2}} \cdot \frac{1}{x^2 + 6} \cdot (2 \cdot x^{2 - 1} + 0)$
[Derivative] Simplify: $\displaystyle y' = \frac{3}{2}ln(x^2 + 6)^{\frac{1}{2}} \cdot \frac{1}{x^2 + 6} \cdot (2x)$
[Derivative] Multiply: $\displaystyle y' = \frac{3ln(x^2 + 6)^{\frac{1}{2}}}{2} \cdot \frac{1}{x^2 + 6} \cdot (2x)$
[Derivative] Multiply: $\displaystyle y' = \frac{3ln(x^2 + 6)^{\frac{1}{2}}}{2(x^2 + 6)} \cdot (2x)$
[Derivative] Multiply: $\displaystyle y' = \frac{3(2x)ln(x^2 + 6)^{\frac{1}{2}}}{2(x^2 + 6)}$
[Derivative] Multiply: $\displaystyle y' = \frac{6xln(x^2 + 6)^{\frac{1}{2}}}{2(x^2 + 6)}$
[Derivative] Factor: $\displaystyle y' = \frac{2(3x)ln(x^2 + 6)^{\frac{1}{2}}}{2(x^2 + 6)}$
[Derivative] Simplify: $\displaystyle y' = \frac{3xln(x^2 + 6)^{\frac{1}{2}}}{x^2 + 6}$

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

3 0

3 years ago