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3 years ago

Describe and correct the error in finding the value of the power.

Mathematics

2 answers:

love history [14]3 years ago

5 0

Answer:

regular number; base

Step-by-step explanation:

Vesna [10]3 years ago

3 0

Answer:

1. Multiplication

2. 8

3. 8^3=512

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What’s (19x+3x)-(56-9x)=Y?

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12x - 56 = y. Hope it helps! :) If you could vote my answer as the brainiest, that would be awesome! :)

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3 years ago

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What is a ratio equivalent to 3:2? (not 6:1)

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9:6, 12:8, and 15:10 are all ratios equivalent to 3:2

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To find an equal ratio, you can either multiply or divide each term in the ratio by the same number (but not zero).

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What is the value of -9 1/5 - 10 + 2/5 + 2(14 1/2 - 7)?

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2 years ago

A ream of paper containing 500 sheets is 5 cm thick. How many sheets of this type of paper would there be in a stack 7.5 cm high

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2 years ago

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A huge ice glacier in the Himalayas initially covered an area of 454545 square kilometers. Because of changing weather patterns,

zloy xaker [14]

Answer:

$t=-20ln\left(\dfrac{1}{3}\right)$

Step-by-step explanation:

The relationship between A, the area of the glacier in square kilometers, and t, the number of years the glacier has been melting, is modeled by the equation.:

$A=45e^{-0.05t}$

We want to determine the value of t for which the area, A(t)=15 square kilometers.

$15=45e^{-0.05t}\\$Divide both sides by 45\\\dfrac{15}{45} =\dfrac{45e^{-0.05t}}{45}\\\dfrac{1}{3}=e^{-0.05t}\\$Take the natural logarithm of both sides\\ln\left(\dfrac{1}{3}\right)=ln\left(e^{-0.05t}\right)\\ln\left(\dfrac{1}{3}\right)=-0.05t\\$Divide both sides by -0.05$\\t=-\dfrac{ln\left(\dfrac{1}{3}\right)}{0.05} \\=-\dfrac{ln\left(\dfrac{1}{3}\right)}{0.05}\\t=-20ln\left(\dfrac{1}{3}\right)$

Therefore, the time for which the area will be 15 sqyare kilometers is:

-20 ln(1/3) years.

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3 years ago