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2 years ago

8

NEED HELP ASAP!!!

1 answer:

Reika [66]2 years ago

5 0

To effectively and correctly answer this and help we'll need a photo diagram for the question. We need to see a graph of some sort to even know where to start this off. It'd probably be solvable without a diagram if you don't have one, but I don't think that many people have the skill to do so (at least I don't). I know how terrible I feel when no one answers my questions, so I thought I'd let you know why others might not be answering this for you. I'm pretty sure you can update the question and attach a photo (an actual photo or a screenshot) to it, via the paperclip icon. Have a great day! :)

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What is the slope of the line passing through the points (-1,-7) and (-9,-2)?

nalin [4]

Answer: m = -5/8

Step-by-step explanation:

The general equation for slope is rise over run, also known as:

m=(y2-y1)/(x2-x1)

From the points (x, y), we can get all the variables we need.

(-1, -7) gives us x1 = -1 and y1 = -7

(-9, -2) gives us x2 = -9 and y2 = -2

If we plug all the values in, we get:

m = (-2 - (-7))/(-9 - (-1))

m = (-2 + 7)/(-9 + 1) the negatives cancel

m = (5)/(-8)

m = -5/8

7 0

3 years ago

A triangle has a base of 3⅖ inches and an area of 5⅒ square inches. Find the height of the triangle. Show your reasoning

N76 [4]

Answer: 3 in.

Step-by-step explanation:

Given

The base of the triangle is $3\frac{2}{5}\ inches$

The area of the triangle is $5\frac{1}{10}\ inches^2$

Solve mixed fraction

Base is

$=3\dfrac{2}{5}\\\\=\dfrac{17}{5}\ in.$

Area is

$=5\dfrac{1}{10}\\\\=\dfrac{51}{10}\ in.^2$

The area of the triangle is given by

$\Rightarrow \text{Area A=}\dfrac{1}{2}\times \text{base}\times \text{height}$

Insert the values to get the height

$\Rightarrow \dfrac{51}{10}=\dfrac{1}{2}\times \dfrac{17}{5}\times \text{height}\\\\\Rightarrow \text{height}=3\ in.$

8 0

2 years ago

Consider the linear equation 2/5x+y=11. will you choose to fix x or y?

sukhopar [10]

Y is the easiest to fix because it has no coefficient, and is therefore the easiest to set on the other side of the equation by itself

4 0

3 years ago

What is the cube root of 27a^l2?<br>-3a4<br>-3a<br> 3a<br> 3a*

GuDViN [60]

Answer:

$3a^4$

Step-by-step explanation:

What is the cube root of $27a^{12}$ ? This is the question.

We can write:

$\sqrt[3]{27a^{12}}$

We will use the below property to simplify:

$\sqrt[n]{a*b}=\sqrt[n]{a} \sqrt[n]{b}$

So, we have:

$\sqrt[3]{27a^{12}} =\sqrt[3]{27} \sqrt[3]{a^{12}}$

We will now use below property to further simplify:

$\sqrt[n]{x} =x^{\frac{1}{n}}$

Thus, we have:

$\sqrt[3]{27} \sqrt[3]{a^{12}} =3*(a^{12})^{\frac{1}{3}}$

We know power to the power rule: $(a^z)^b=a^{zb}$

Now, we have:

$3*(a^{12})^{\frac{1}{3}}\\=3*a^{\frac{12}{3}}\\=3a^4$

This is the correct answer: $3a^4$

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3 years ago

Evaluate the expression. 1− 6P4/ 8P6

allochka39001 [22]

4p^2-3/4p^2. I hope that help..

6 0

2 years ago