Answer:
D
Step-by-step explanation:
Start by writing out w in terms of x. After one year, there is 1.08*x dollars in the account. x dollars are then deposited, giving us a total of 1.08*x + x (normally we would simplify this to 2.08 but looking at the answers this is not a good idea.) Next, multiply by 1.08 to account for the 2nd year's interest. This brings to total to w = 1.08(1.08*x + x) = (1.08^2)*x + 1.08*x. Factoring out x, we are left with w = (1.08^2 + 1.08) * x. Dividing both sides by (1.08^2 + 1.08), we are left with x = w/(1.08^2 + 1.08) so the answer is d.
Let the number of bags that he would have been used to put 3 kg of apples be x. Thus the number of bags that would be used to put 2kgs will therefore be (x+9), hence the total number of kgs the bags will hold will be given by:
3*x=3x kgs
2(x+9)=(2x+18) kgs
since the total weights are the same then:
2x+18=3x
hence
18=3x-2x
18=x
thus the number of bags required to put 3 kgs of apples will be 18. Thus the total Kgs of apples was:
3x
=3*18
=54 kgs
I think you mean y=ab^x.
First, plug in the values of x=2 and y=24 for the first equation, and x=3 and y=48 for the second one:
24 = ab^2
48 = ab^3
divide equation 2 by equation 1:
2 = b^1
or, more simply:
2 = b
now plug b into one of the equations to get "a":
24 = a*2^2
24 = a*4
6 = a
So, the answer is y = 6(2)^x
(I think you need to specify the power of x in your answers)
