Given
s=16t^2
where
s=distance in feet travelled (downwards) since airborne with zero vertical velocity and zero air-resistance
t=time in seconds after release
Here we're given
s=144 feet
=>
s=144=16t^2
=>
t^2=144/16=9
so
t=3
Ans. after 3 seconds, the object hits the ground 144 ft. below.
Answer:
2 to 8 pounds his can gain.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
1.2 inches
Step-by-step explanation:
Area of sphere
A = 4πr²
17.6 = 4(3.14)r²
17.6 = 12.56r²
Divide both sides by 12.56
1.4012738854 = r²
Take the sqaure root of both sides
1.1837541491 = r
Rounded
r = 1.2
