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3 years ago

26 1/4 divided by 1 3/4

Mathematics

1 answer:

maria [59]3 years ago

3 0

The answer you are looking for is 0.14285714285

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The grocery store sells kumquats for $5.00 a pound and Asian pears for $3.25 a pound. Write an equation in standard form for the

aniked [119]

Okay so your equation is going to be : 18= 5k + 3.25p

3 0

3 years ago

Read 2 more answers

What is the solution of the equation below?<br> x² - 4= - 5

madam [21]

Answer:

Not possible to work out

Step-by-step explanation:

NO Explanation can be explained as this question cannot be solved

8 0

3 years ago

cindy,jamal,and monique are dividing a piece of land using the lone divider method.after flipping coins monique has been selecte

lukranit [14]

9514 1404 393

Answer:

The (piece, perceived values) are ...

Cindy, (3, 48%)
Jamal, (1, 39%)
Monique, (2, 33%)

Step-by-step explanation:

We assume the values and questions are as shown in the attachment.

1. After the division, Cindy bids only on piece 3, and Jamal bids only on piece 1. Hence the appropriate final division is ...

Cindy: piece 3

Jamal: piece 1

Monique: piece 2

2. Monique divides the land so that the value of each piece to her is 33 1/3%. That is her perceived value for the piece she gets.

7 0

3 years ago

Myra likes blueberry yogurt, but cherry yogurt is her favorite. Yesterday, she bought 3 cartons of cherry yogurt for every 2 car

cupoosta [38]

Answer:

9 cherry, 6 blueberry

Step-by-step explanation:

lets do a table!

cherry | blueberry

----------------------------

3 2

6 4

9 6

When there are 2 blueberry, there are 3 cherry. 3 is 1 more than 2. When there are 4 blueberry, there are 6 cherry. 6 is 2 more than 4. When there are 6 blueberry, there aare 9 cherry. 9 is 3 more than 6.

7 0

3 years ago

A study is conducted to determine if a newly designed text book is more helpful to learning the material than the old edition. T

Oksanka [162]

Answer:

The null and alternative hypotheses are:

$H_{0}:\mu=75$

$H_{a} : \mu>75$

Under the null hypothesis, the test statistic is:

$t=\frac{\bar{x}-\mu}{\frac{s}{\sqrt{n}} }$

Where:

$\bar{x} =83$ is the sample mean

$s=9.8206$ is the sample standard deviation

$n=10$ is the sample size

$\therefore t= \frac{83-75}{\frac{9.8206}{\sqrt{10}} }$

$=2.58$

Now, we can find the right tailed t critical value at 0.01 significance level for df = n-1 = 10 - 1 = 9 using the t distribution table. The t critical value is given below:

$t_{critical} =2.821$

Since the test statistic is less than the t critical value, we therefore, fail to reject the null hypothesis and conclude that there is not sufficient evidence to support the claim that the people do better with the new edition.

7 0

3 years ago