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andrew-mc [135]
3 years ago
13

26 1/4 divided by 1 3/4

Mathematics
1 answer:
maria [59]3 years ago
3 0
The answer you are looking for is 0.14285714285
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Kamil is saving up to buy a model of Big Ben costing £30 when he visits London. So far he has saved €15.00. How much more money
Naddika [18.5K]

Answer:

€18.40 or £16.53.

Step-by-step explanation:

Kamil is saving up to buy a model of Big Ben costing £30 when he visits London.

He has saved €15.00.

First, we have to convert his savings to Pounds(£) and then, subtract that from the amount he needs.

€1  = £0.90

€15 = 15 * 0.9 = £13.47

So, Kamil has saved  £13.47.

Therefore, the amount he has left to save is:

£30 -  £13.47 =  £16.53

To find this amount in Euros, we convert it to Euros:

£1 = €1.11

16.53 = 16.53 * 1.11 = €18.40

He has to save €18.40 or £16.53.

8 0
4 years ago
Read 2 more answers
What is the value of 5a + 7b if a = 4 and b = 3
Andreas93 [3]

Answer:

= 41

Step-by-step explanation:

plug in the numbers for the variables

5(4) + 7(3)

multiply

20 + 21

add together

= 41

4 0
3 years ago
Read 2 more answers
What is 1.1428571429 as a what is fraction
polet [3.4K]
11428571429/10000000000 because all you have to do is say the number as a decimal and count the place values
7 0
3 years ago
One pipe can fill a tank in 8 minutes and second pipe can
Vanyuwa [196]

Answer:

4.8 minutes

Step-by-step explanation:

Pipe 1= 1/8 per min or 3/24

Pipe 2= 1/12 per min or 2/24

(2/24)+(3/24)= 5/24

24÷5= 4.8 min

4 0
3 years ago
I need help finding this answer ASAP
Darya [45]

Answer:

First & Third options

Step-by-step explanation:

\bigg( {5}^{ \frac{3}{8}} \: . {5}^{ \frac{1}{8}}  \bigg)^{3}  \\  \\  = \bigg( {5}^{ \frac{3}{8} + \frac{1}{8}}   \bigg)^{3}  \\   \\  = \bigg( {5}^{ \frac{4}{8}}   \bigg)^{3}   \\   \\  = \bigg( {5}^{ \frac{1}{2}}   \bigg)^{3}  \\  \\ =  {5}^{ \frac{3}{2}}    \\  \\  =  \sqrt{ {5}^{3} }   \\  \\      \huge\red{ \boxed{\therefore \bigg( {5}^{ \frac{3}{8}} \: . {5}^{ \frac{1}{8}}  \bigg)^{3}=  \sqrt{ {5}^{3} } }}

8 0
4 years ago
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