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3 years ago

(66 x 10) - (9.9 x 104)

2 answers:

7 0

Simply whats in the parenthesis first. Your equation will now look like this:
(660)-(1029.6)

Simply.
369.6

369.6 should be your answer

Sidana [21]3 years ago

3 0

66x10=660

9.9x104=1029.6

660-1029.6=-369.6

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(ii) Hence solve the following system of simultaneous equations:

gladu [14]

Answer:

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2 years ago

The sum of two.number is.24. the.sun.of the square.of the two.nunber is 306. what is the product.of the two.number

tresset_1 [31]

A) x + y = 24
B) x^2 + y^2 = 306

A) x = 24 -y
Then substituting this into B)
(24 - y)^2 +y^2 = 306
576 -48y +y^2 + y^2 = 306
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3 years ago

I need help with this question it's really hardd

Vsevolod [243]

1st one on second row I think

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3 years ago

A data set includes 103 body temperatures of healthy adult humans having a mean of 98.3degreesF and a standard deviation of 0.73

faust18 [17]

Answer:

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher

Step-by-step explanation:

Data provided in the question:

sample size, n = 103

Mean temperature, μ = 98.3

Standard deviation, σ = 0.73

Degrees of freedom, df = n - 1 = 102

Now,

For Confidence level of 99%, and df = 102, the t-value = 2.62 [from the standard t table]

Therefore,

CI = $(Mean - \frac{t\times\sigma}{\sqrt{n}},Mean + \frac{t\times\sigma}{\sqrt{n}})$

Thus,

Lower limit of CI = $(Mean - \frac{t\times\sigma}{\sqrt{n}})$

Lower limit of CI = $(98.3 - \frac{2.62\times0.73}{\sqrt{103}})$

Lower limit of CI = 98.11

and,

Upper limit of CI = $(Mean + \frac{t\times\sigma}{\sqrt{n}})$

Upper limit of CI = $(98.3 + \frac{2.62\times0.73}{\sqrt{103}})$

Upper limit of CI = 98.49

Hence,

CI = (98.11 , 98.49)

The value of 98.6°F suggests that this is significantly higher and the mean temperature could very possibly be 98.6°F

7 0

3 years ago

9 is 1/10 of what number

Oxana [17]

9 is 1/10 of 90 because if you add 1 zero it is 90

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3 years ago

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