All categories

3 years ago

The perimeter of kite LMNO is 36 feet. Side MN = 8x – 3 and side NO = 2x + 1. Find the value of x.

Mathematics

2 answers:

AlekseyPX3 years ago

5 0

Answer: 85.333 or 256 over 3.

motikmotik3 years ago

4 0

Answer: x = 2

Step-by-step explanation:

The diagram of the kite is shown in the attached photo.

The perimeter of the kite is the distance around the kite.

The kite has 2 pairs of equal sides.

This means that

Side ML = side MN and side NO =

side LO

If Side MN = 8x – 3 and side NO = 2x + 1, then The perimeter of the kite is ML + MN + NO + LO

The perimeter of kite LMNO is given as 36 feet.

Therefore

ML + MN + NO + LO = 36

8x – 3 + 2x + 1 +8x – 3 + 2x + 1 = 36

8x + 8x + 2x+ 2x -3 +1 - 3 + 1

20x -4 = 36

20x = 40

x = 40/20 = 2

You might be interested in

Help it’s for a quiz

Vilka [71]

Answer:

i cant answer that

Step-by-step explanation: I cant answer because if it was for a quiz i bet the quiz is over now so there is no point in answering.

6 0

2 years ago

Six equilateral triangles are connected to create a regular hexagon. The area of the hexagon is 24a^2 – 18 square units. Which i

netineya [11]

we know that

The area of the hexagon is equal to the sum of the areas of the six equilateral triangles

Let

x-------> area of one equilateral triangle

$6x=24a^{2} -18$

Divide by $6$ both sides

$x=4a^{2} -3$ -------> area of one equilateral triangle

To find an equivalent expression for the area of the hexagon based on the area of a triangle, multiply the area of one equilateral triangle by $6$

$6*(4a^{2} -3)$

therefore

the answer is

The equivalent expression is equal to $6*(4a^{2} -3)$

6 0

3 years ago

Read 2 more answers

The slope of the line tangent to the curve y^2 + (xy+1)^3 = 0 at (2, -1) is ...?

Lina20 [59]

$\frac{d}{dx}(y^2 + (xy+1)^3 = 0)
\\
\\\frac{d}{dx}y^2 + \frac{d}{dx}(xy+1)^3 = \frac{d}{dx}0
\\
\\\frac{dy}{dx}2y + \frac{d}{dx}(xy+1)\ *3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{d}{dx}(xy)+\frac{d}{dx}1\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{d}{dx}xy+x\frac{d}{dx}y+\frac{dx}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(\frac{dx}{dx}y+x\frac{dy}{dx}+\frac{dx}{dx}0\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0$
$\frac{dy}{dx}2y + \left(y+x\frac{dy}{dx}\right)\ * 3(xy+1)^2 = 0
\\
\\\frac{dy}{dx}2y + \left(3y+3x\frac{dy}{dx}\right) (xy+1)^2 = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) (xy+1)^2 = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + \left(3y+3x\ y'\right) ((xy)^2+2xy+1) = 0
\\
\\2y\ y' + 3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y') = 0
\\
\\3x^2y^3 +6xy^2+3y+(3x y' +6x^2y y'+3x^2y y'+2yy' ) = 0
\\
\\y'(3x +6x^2y+3x^2y+2y ) = -3x^2y^3 -6xy^2-3y

$
$y' = \frac{-3x^2y^3 -6xy^2-3y}{(3x +6x^2y+3x^2y+2y )};\ x=2,y=-1
\\
\\y' = \frac{-3(2)^2(-1)^3 -6(2)(-1)^2-3(-1)}{(3(2) +6(2)^2(-1)+3(2)^2(-1)+2(-1) )}
\\
\\y' = \frac{-3(4)(-1) -6(2)(1)+3}{(6 +6(4)(-1)+3(4)(-1)-2 )}
\\
\\y' = \frac{12 -12+3}{(6 -24-12-2 )}
\\
\\y' = \frac{3}{( -32 )}$

7 0

3 years ago

Area of combined rectangles #1

zzz [600]

Answer:

hahaeejejejejeueuehe equal148176

4 0

3 years ago

Joe is 10 years older than James and eight years twice Joe’s age will equal three times James eight how old is Joe now.

Lady_Fox [76]

Let James be x years old
Joe = 10 + x
After 8 years
18 + x = 3(x)
18 + x = 3x
18 = 2x
x = 9

Joe is 19
James is 9

6 0

3 years ago