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sleet_krkn [62]
3 years ago
7

4, 12, 36, 108 , ... this means Arithmetical or Not Arithmetical​

Mathematics
1 answer:
jolli1 [7]3 years ago
8 0

\text{Hello there!}\\\\\boxed{\text{This would not be an arithmetical sequence}}\\\\\text{This is not an arithmetic sequence because the common number is}\\\text{not adding.}\\\\\text{The sequence in the question would be known as a geometric sequence}\\\\\text{A geometric sequence multiplies by a common ratio, and that's what the}\\\text{sequence is doing}\\\\\text{The sequence is being multiplied by a common ratio of 3}

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Find the equation of the axis of symmetry of the following parabola algebraically.<br> y=2x^2+16.
Inessa05 [86]

Answer:

x = 0

axis of symmbery = -b/2a or x vertex on quadratic equation

0/4=0

x=0

Step-by-step explanation:

3 0
3 years ago
The national mall is approximately 6,400,000 ft.². If an event organizer estimate the density at 4 ft.² per person, approximatel
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1,600,000

Step-by-step explanation:

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3 years ago
Write each expression as a single power of 10​
swat32

Answer:

<u>It</u><u> </u><u>is</u><u> </u>

<u>{10}^{5}</u>

Step-by-step explanation:

\frac{ {10}^{4}. {10}^{5}  . {10}^{6} }{ {10}^{3} . {10}^{7} }  =  \frac{ {10}^{(4 + 5 + 6)} }{ {10}^{(3 + 7)} }  \\  \\  =  \frac{ {10}^{15} }{ {10}^{10} }  \\  \\  =   {10}^{(15 - 10)}  \\  =  {10}^{5}

3 0
3 years ago
Polygon LMNO is similar to polygon QRST, and I and QR are
Oksana_A [137]

Answer:

Step-by-step explanation:

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8 0
3 years ago
Solve for x: 3/3x + 1/x+4 = 10/7x
Mekhanik [1.2K]
Given,

3/3x + 1/(x + 4) = 10/7x

1/x + 1/(x+4) = 10/7x

Because the first term on LHS has 'x' in the denominator and the second term in the LHS has '(x + 4)' in the denominator. So to get a common denominator, multiply and divide the first term with '(x + 4)' and the second term with 'x' as shown below

{(1/x)(x + 4)/(x + 4)} + {(1/(x + 4))(x/x)} = 10/7x

{(1(x + 4))/(x(x + 4))} + {(1x)/(x(x + 4))} = 10/7x

Now the common denominator for both terms is (x(x + 4)); so combining the numerators, we get,

{1(x + 4) + 1x} / {x(x + 4)} = 10/7x

(x + 4 + 1x) / (x(x + 4)) = 10/7x

(2x + 4) / (x(x + 4)) = 10/7x

In order to have the same denominator for both LHS and RHS, multiply and divide the LHS by '7' and the RHS by '(x + 4)'

{(2x+4) / (x(x + 4))} (7 / 7) = (10 / 7x) {(x + 4) / (x + 4)}

(14x + 28) / (7x(x + 4)) = (10x + 40) / (7x(x + 4))

Now both LHS and RHS have the same denominator. These can be cancelled. 

∴14x + 28 = 10x + 40
14x - 10x = 40 - 28
4x = 12
x = 12/4

∴x = 3



8 0
3 years ago
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