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Talja [164]
3 years ago
12

Which of the following is the solution of –6x – 17 = 19?

Mathematics
2 answers:
Ostrovityanka [42]3 years ago
4 0
-6x=19+17
-6x=36 /(-6)
x=-6
vesna_86 [32]3 years ago
4 0

-6x-17=19

     +17 +17

_____________

-6x=36

__   __

-6    -6

x= -6

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What is the sum of the measures of the exterior angles in a nonagon? explain
DedPeter [7]

The sum of the measures of all exterior angle in a polygon with n sides is always 360^{\circ}.

Nonagon is a polygon with 9 sides. If this nonagon is regular or equiangular, then all interior angle are congruent, and therefore all exterior angles are congruent. Then the measure of each exterior angle is \dfrac{360^{\circ}}{9} =40^{\circ}.

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The answer is: x is choose your answer
katrin2010 [14]

Answer:

All real numbers

Let's find the critical points of the inequality.

−4x+7=17

−4x+7+−7=17+−7(Add -7 to both sides)

−4x=10

−4x−1=10−1

(Divide both sides by -1)

4x=−10

4x=−10(Solve Exponent)

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x*(log(4))=log(−10)

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3 years ago
Hey guys<br>im new here<br>please solve this for me with steps!<br>ill mark as the best answer​
Vinil7 [7]

Answer:

The factors of  2(x+y)^2-9(x+y)-5 is ((x+y)-5)(2x+2y+1)

Step-by-step explanation:

Given polynomial

=>2(x+y)^2-9(x+y)-5

To Find:

The factors of the polynomial =?

Solution:

Lets assume  k = (x+y)

Then 2(x+y)^2-9(x+y)-5 can be written as 2k^2-9k-5

Now by using quadratic formula

k =\frac{-b\pm\sqrt{(b^2-4ac}}{2a}

where

a= 2

b= -9

c= -5

Substituting the values, we get

k =\frac{-b\pm\sqrt{(b^2-4ac)}}{2a}

k =\frac{-(-9) \pm \sqrt{((-9)^2-4(2)(-5)}}{2(2))}

k =\frac{-(-9) \pm \sqrt{(81+40)}}{4}

k =\frac{-(-9) \pm \sqrt{(121)}}{4}

k =\frac{-(-9) \pm 11}}{4}

k= \frac{ 9 \pm 11}{4}

k =  \frac{20}{4}                         k =  \frac{-2}{4}    

k_1 =5                                      k_2 = -\frac{1}{2}

2k^2-9k-5= 2(k-5)(k+\frac{1}{2})

Solving the RHS we get

\frac{2}{2}(k-5)(2k+1)

(k-5)(2k+1)

Substituting k = x+y

((x+y)-5)(2(x+y+1)

((x+y)-5)(2x+2y+1)

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Answer:

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