Question

Help me with number 3 pleaseeeeeeeeeee!!!!!!!!!!!!!!!!!

Answer 1

Given:

∠M = 0.775 radians, m = 5 ft, n = 7 ft, p = 4 ft

To find:

The measure of angle P.

Solution:

Using law of cosine:

$p^2=m^2+n^2-2mn \cos P$

Substitute the given values.

$4^2=5^2+7^2-2\times 5 \times 7 \cos P$

$16=25+49-70 \cos P$

$16=74-70 \cos P$

Subtract 74 from both sides.

$16-74=74-70 \cos P-74$

$-58=-70 \cos P$

Multiply by -70 on both sides.

$\frac{-58}{-70} =\frac{-70 \cos P}{-70}$

$\frac{29}{35} = \cos P$

$\cos^{-1} \frac{29}{35} = P$

$34^\circ = P$

The measure of angle P is 34°.