y + 6 = 4/3(x - 2)
First, distribute the 4/3
y + 6 = 4/3x - 8/3
Subtract 6 from both sides.
y = 4/3x - 26/3
-26/3 is the y-intercept so start the graph at coordinate (0, -26/3)
After you plot the y-intercept, add 4 to they y-coordinate and 3 to the x-coordinate of the y-intercept to get the next point.
0 + 3 = 3
-26/3 + 4 = -14/3
The next point should be at (3, -14/3)
Add as many points as your professor requires.
Answer:
All except one interval [-2,8]
Step-by-step explanation:
Notice that the function, wich an hyperbola, has a vertical asymptote in both -2 and 8 and there is nothing between this two values.
So we will exclude what's between them out of the domain.
Answer:
20, 60, 15
Step-by-step explanation:
Let the third number be n, then
The first number is n + 5 and the second number is 4n
Sum the 3 numbers and equate to 95, that is
n + 5 + 4n + n = 95 ← collect like terms on left side
6n + 5 = 95 ( subtract 5 from both sides )
6n = 90 ( divide both sides by 6 )
n = 15
Thus
The first number is 15 + 5 = 20
The second number is 4 × 15 = 60
The third number is 15
Answer:
72
Step-by-step explanation:
Let the number of candies = n
Tracy ate = 1/3 of n = n/3 remaining 2n / 3
she gave 1/4 of the remainder to her friend = 1/4 of ( n - n/3) = 2n / 12
the new remainder = (2n / 3) - (2n / 12) = n /2
she and her mom then ate altogether = 30
and the brother took from 1 to five, the number he took = x
and she has 3 left
( n/2) - 30 - x = 3
n = 2 ( 33 + x)
now we know that the candies could not be broken and x is between 1 to 5
n = 2 (33 + 1), 2 (33+2), 2(33 +3), 2 (33+ 4) and 2 (33 + 5) this are the possible values of n, ( 68, 70, 72, 74, 76) and the multiple of 3 is 72
n therefore = 72
