(a + 1)(a² + 2a + 1)
= a(a² + 2a + 1) + 1(a² + 2a + 1)
= a³ + 2a² + a + a² + 2a + 1
= a³ + 3a² + 3a + 1
Answer: b
Answer:
-74
Step-by-step explanation:
Graph the function. See attached picture. Between the interval where -4 > x < 0, the graph rises up to a peak and descends back down when x = 0. This means the minimum value will be where x = -4.
Substitute x = -4 into the equation.
f(-4) = (-4)^3 -3(-4)^2 - 9(-4) + 2
f(-4) = -64 -3(16) +36 + 2
f(-4) = -64 - 48 + 36 + 2
f(-4) = -74
Answer:
Calgary is the coldest
Step-by-step explanation:
The simple way to determine this will be to change the value of temperatures given in Fahrenheit to Celsius
32 F = 0°C
Formula to apply will be (T-32)×5/9 -------------where T is temperatures in Fahrenheit
Bangor is -3F-------------------change to Celsius
(-3-32)×5/9 =-35 × 5/9 = -19.44°C
Fairbanks is -12 ------------------------change to Celsius
(-12-32)×5/9 = -44 × 5/9 = -24.44°C
Fargo is -8 F ---------------------Change to Celsius
(-8-32)×5/9= -40×5/9 = -22.22°C
Calgary is -15 F-------------------------Change to Celsius
(-15-32)×5/9 = -47×5/9 = -26.11°C--------------coldest
Answer:
![Area = 270m^2](https://tex.z-dn.net/?f=Area%20%3D%20270m%5E2)
Step-by-step explanation:
Given
![A = \frac{1}{2}bh](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B1%7D%7B2%7Dbh)
![b = 18m](https://tex.z-dn.net/?f=b%20%3D%2018m)
![h = 30m](https://tex.z-dn.net/?f=h%20%3D%2030m)
Required
Solve for A
Simply substitute 18 for b and 30 for h
![A = \frac{1}{2}bh](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B1%7D%7B2%7Dbh)
![A = \frac{1}{2} * 18 * 30](https://tex.z-dn.net/?f=A%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%2A%2018%20%2A%2030)
![A = 270](https://tex.z-dn.net/?f=A%20%3D%20270)
Hence:
The area is
![Area = 270m^2](https://tex.z-dn.net/?f=Area%20%3D%20270m%5E2)