Answer:
-6 ≥ r
Step-by-step explanation:
–5 ≥ 5 (r+5)
Divide each side by 5
–5/5 ≥ 5/5 (r+5)
–1 ≥ (r+5)
Subtract 5 from each side
-1-5 ≥ r+5-5
-6 ≥ r
A' (3(-5),3(-4))= (-15,-12)
B' (3(2),3(6))=(6,18)
C'(3(4),3(-3))=(12,-9)
Let n represent the number.
<span>.. (3/5)n - 1 = 23 ... three-fifths of a number decreased by one is twenty-three. </span>
<span>Please note that the same English description might be interpreted as </span>
<span>.. (3/5)(n-1) = 23. </span>
<span>We'll use the first interpretation, as it results in the number being an integer. </span>
<span>.. (3/5)n = 24 ... add 1 </span>
<span>.. n = (5/3)*24 ... multiply by 5/3 </span>
<span>.. n = 40 ... carry out the multiplication </span>
<span>The number is 40.</span>
45n+15
Factor out 15 from the expression
15(3n+1)