PLEASE DO NOT CLICK THE LINK THAT PERSON SENT YOU ITS A VIRUS
Answer:
y-3
Problem:
What is the remainder when the dividend is xy-3, the divisor is y, and the quotient is x-1. ?
Step-by-step explanation:
Dividend=quotient×divisor+remainder
So we have
xy-3=(x-1)×(y)+remainder
xy-3=(xy-y)+remainder *distributive property
Now we just need to figure out what polynomial goes in for the remainder so this will be a true identity.
We need to get rid of minus y so we need plus y in the remainder.
We also need minus 3 in the remainder.
So the remainder is y-3.
Let's try it out:
xy-3=(xy-y)+remainder
xy-3=(xy-y)+(y-3)
xy-3=xy-3 is what we wanted so we are done here.
Answer:
a
Step-by-step explanation:
Let the speed of the current equal c
and the speed of the boat in still water equal b.
b + c = 1.5 (b - c)
b + c = 1.5b - 1.5c
0.5b = 2.5c
b = 5c
The speed of the current is 1.5 mph so
b = 5 * 1.5 = 7.5 mph
For this one, find out how many hour have passed per day with 6 pm Friday being where you start.
6 pm Friday- 6 pm Saturday =24
6 pm Saturday - 6 pm Sunday= 24
6 pm Sunday - 6 am Monday = 12 hours
6 am Monday until 8 am Monday= 2 hours
Now just add the amount of hours together
24+24+12+2= 62 hours
Now convert that to minutes.
There are 60 minutes in 1 hour. You multiply the amount of hours by 60 to get the minutes.
62 hours times 60 minutes in 1 hour
62*60= 3720.
So you will have a total of 3,720 minutes of tape to review.
