Question

Chenoa starts with $250 in her savings account. Each month she adds $15.

Answer 1

Chenoa starts with $250 in her saving account and each month she adds $15 in her saving account.

Therefore, we obtain a sequence as:

250, (250+15), (250+15+15),...

250, 265, 280,....

So, we get the first term ($a_{1}$) as 250.

Now , we can clearly observe that the first term is 250 and second term is obtained by adding 15 to the first term that is 265 and so on.

Similarly in an arithmetic progression, last term is $a_{n}$ and its previous term is $a_{n-1}$.

Similarly, $a_{n}$ will be obtained by adding 15 to its previous term $a_{n-1}$.

So, $a_{n}=15+a_{n-1}$ and $a_{1}$=250.

Therefore, Option C is correct.

Answer 2

The answer could be B.