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Ainat [17]
3 years ago
6

How do I solve for x?

Mathematics
1 answer:
Lerok [7]3 years ago
3 0

Answer:

x=11 degrees

Step-by-step explanation:

There's a property of a triangle where the sum of two of the interior angles is equal to 180-(last interior angle). In this case, 180-(last interior angle) is equal to 7x-1, because angles BAE and BAC are supplementary, which means that they add up to 180 degrees.

So, we can set up an equation

(56)+(2x-2)=(7x-1)

Solving, we get

56+2x-2=7x-1

56-2=5x-1

54+1=5x

55=5x

11=x

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Step-by-step explanation:

7 0
3 years ago
Solve 5y'' + 3y' – 2y = 0, y(0) = 0, y'(O) = 2.8 y(t) =( Preview
Karolina [17]

Answer:

y=\frac{4}{5}e^{t}-\frac{4}{5}e^{-\frac{2}{5}t}

Step-by-step explanation:

The given equation 5y'' + 3y' - 2y =0 can be written as

(5D^{2}+3D-2)y(t)=0

Solving for complementary function we have Roots of (5D^{2}+3D-2) as follows

(5D^{2}+5D-2D-2)

5D(D+1)-2(D+1)=0\\\\(5D-2)(D+1)=0\\\\\therefore D=-1\\D=+2/5

Thus the complementary function becomes

y=y=c_{1}e^{m_{1}t}+c_{2}e^{m_{2}t}

where

m_{1},m_{2} are calculated roots

thus solution becomes

y=c_{1}e^{-t}+c_{2}e^{\frac{2}{5}t}

Now to solve for the coefficients we use the given boundary conditions

y(0)=0\\\\\therefore c_{1}+c_{2}=0\\\\y'(0)=-c_{1}+\frac{2}{5}c_{2}=2.8\\\\\therefore c_{2}+\frac{2}{5}c_{2}=2.8\\\\c_{2}=2\\\\\therefore c_{1}=-2}

hence the solution becomes

y=-2e^-{t}+2e^{\frac{2}{5}t}

8 0
3 years ago
18 + 4(3x - 7) = -70
Elan Coil [88]
If you’re trying to find the value of x it is -5
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3 years ago
Write an equation of the line passing through the point (3, 4) that is parallel to the line −2x+3y=2
mote1985 [20]

Parallel lines have same slope, so first isolate y to get the equation into y=mx+b form.

-2x+3y=2

3y = 2x + 2

y = \frac{2x+2}{3}

Now plug the point (3,4) into y = 2x + b

4 = 2(3) + b

Solves for be

b = -2

So the new equation is y = 2x - 2

5 0
3 years ago
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Talja [164]
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3 years ago
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