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serious [3.7K]
3 years ago
15

Express 0.18 as a fraction in lowest terms. A:10/18 B:9/50 C:18/100 D:3/16

Mathematics
2 answers:
almond37 [142]3 years ago
7 0
The answer is 9/50 because 10/18 cannot be deduced from 0.18, 18/100 is not simplified and 3/16 doesn't work.
ohaa [14]3 years ago
3 0
Not exactly sure what you mean by lowest terms but it seems the answer would be C.
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Please help me again
Vikentia [17]

Answer:

y = 10

Step-by-step explanation:

<u>Since all sides are equal, that means all angles are 60 degrees. 60 + 60 + 60 = 180</u>

<u />

5y + 10 - 10 = 60 - 10

5y / 5 = 50 / 5

y = 10

Answer:  y = 10

7 0
3 years ago
An inequality is shown: −np − 4 ≤ 2(c − 3) Which of the following solves for n?
sesenic [268]

Answer:

\huge\boxed{n\leq\dfrac{2-2c}{p}\ \text{for}\ p0}

Step-by-step explanation:

-np-4\leq2(c-3)\qquad\text{use the distributive property}\\\\-np-4\leq2c-6\qquad\text{add 4 to both sides}\\\\-np\leq2c-2\qquad\text{change the signs}\\\\np\geq2-2c\qquad\text{divide both sides by}\ p\neq0\\\\\text{If}\ p0 ,\ \text{then}\\\boxed{n\geq\dfrac{2-2c}{p}}

6 0
3 years ago
15 plus the difference of 10 and a number X is 15 (X=?)
Verizon [17]
15+(10-x)=15 would be your equation if that is what you are looking for.
5 0
3 years ago
Question 4 (1 point)<br> (-7x + 5) - (-82 – 6) =
Keith_Richards [23]

no ye puedo ayudar amigo o amiga

8 0
3 years ago
PLEASE HELP ME!!!!!!!!!
vitfil [10]
<h2>1)</h2>

(x - 4) {}^{2}  - 28 = 8 \\ (x - 4) {}^{2}  = 8 + 28 \\ (x - 4) {}^{2}  = 36

This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

\sqrt{(x - 4) {}^{2} }  =  ± \sqrt{36}  \\x - 4 = ±6 \\ x _{1}- 4 = 6 \:  \:  \:  \:  \:  \:  \: \:  \:  \:  x _{2}- 4 =  - 6 \\ x_{1} = 6 + 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2} =  - 6 + 4 \\ x_{1} = 10 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: \:  \: x_{2} =  - 2

<h2>2)</h2>

Well he started off correct to the point of completing the square.

(x - 3)  {}^{2}  = 16 \\ x - 3 = ±4 \\  \: x_{1}  - 3 = 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  - 3 =  - 4 \\ x_{1}  = 7 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  =  - 1

8 0
1 year ago
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