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2 years ago

How do you solve this?

Mathematics

1 answer:

mixas84 [53]2 years ago

3 0

Just add the area and multiply by 2

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Solve the system by substitution

Tatiana [17]

Answer:

(x,y) = (-36,6)

Step-by-step explanation:

-6y=x

x+y=-30

x=-6y,

so -6y+y=-30

-5y=-30

y=6

x=-36

Hope this helps pls hit the crown :D

8 0

3 years ago

Distribute! only 5 problems!

Dominik [7]

Answer:

Step-by-step explanation:

4 0

3 years ago

Principal Zimmer wants to make sure that students have enough time to get across campus between classes. To see how long it take

Len [333]

Answer:

the answers is step 3

Step-by-step explanation:

i took the test

7 0

3 years ago

A triangle with side lengths of 5, 5, and 8 is:

Volgvan

Your answer is c, an obtuse triangle because if the two side lengths are the same length along with a longer side, it become obtuse
let me know if you have any other questions
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6 0

3 years ago

Please can someone help me with this question

sasho [114]

Answer:

r = - $\frac{6a}{1-5m^2}$

Step-by-step explanation:

Rewrite the equation as $\sqrt{x} 6a+r/5r$ = m

Remove the radical on the left side of the equation by squaring both sides of the equation.

( $\sqrt{\frac{6a+r}{5r} )^{2}$ = m^2

Then, you simplify each of the equation.

Rewrite: ( $\sqrt{\frac{6a+r}{5r} )^{2}$ as $\frac{6a+r}{5r} = m^{2}$

Remove any parentheses if needed.

Solve for r.

Multiply each term by r and simplify."

Multiply both sides of the equation by 5.

6a+r= m^2r⋅(5)

Remove parentheses.

Move 5 to the left of (m ^2) r

6a+r=5m^2)r

Subtract 5m^2)r from both sides of the equation.

6a+r-5m^2)r=0

Subtract 6a from both sides of the equation.

r-5m^2)r=-6a

Factor r out of r-5m^2)r

r(1-5m^2)=-6a

Divide each term by 1-5m^2 and simplify.

r = - $\frac{6a}{1-5m^2}$

There you go, hope this helps!

4 0

3 years ago