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laila [671]
3 years ago
14

Find 3 points that solve the equation x-4y=-18

Mathematics
2 answers:
zhenek [66]3 years ago
4 0
<h2>Answer:</h2><h2>hope it helps you see the attachment for further information ✌✌✌✌✌</h2>

Eva8 [605]3 years ago
4 0

Answer:

(-18, 0).

(-14, 1).

(-22, -1).

Step-by-step explanation:

x - 4y = -18

x = -18 + 4y

Let y = 0, then  x = -18 so one point is (-18, 0).

Let y = 1 then x = -18+4 = -14 so another point is (-14, 1).

Let y = -1 then x = -18 +4(-1) = -18 - 4 = -22 so another point is (-22, -1).

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creativ13 [48]
I don’t see the graph
6 0
3 years ago
Distance between (-10,9) and (-5,2)
jonny [76]

Answer:

8.60 units (3 s.f.)

Step-by-step explanation:

The distance between 2 points is given by the formula:

\sqrt{(y1 - y2)^{2} +  {(x1 - x2)}^{2}  }

Thus using the above formula,

Distance between (-10, 9) and (-5, 2)

=  \sqrt{ {(9 - 2)}^{2}  +  {( - 10 + 5)}^{2} }  \\  =  \sqrt{ {7}^{2}  + ( - 5)^{2} }  \\  =  \sqrt{74}  \\  = 8.60 \: units \: (3 \: s.f.)

8 0
3 years ago
Two terms of a geometric sequence are given. Find the first five terms. Please help asap
Zepler [3.9K]

Answer:

4, 8, 16, 32, 64

Step-by-step explanation:

The nth term of a geometric sequence is

a_{n} = a₁(r)^{n-1}

Given

a₇ = 256 and a₁₀ = 2048 , then

a₁ r^{6} = 256 → (1)

a₁ r^{9} = 2048 → (2)

Divide (2) by (1)

\frac{a_{1}r^{9}  }{a_{1}r^{6}  } = \frac{2048}{256}

r³ = 8 ( take the cube root of both sides )

r = \sqrt[3]{8} = 2

Substitute r = 2 into (1)

a₁ × 2^{6} = 256

a₁ × 64 = 256 ( divide both sides by 64 )

a₁ = 4

Then

a₁ = 4

a₂ = 2a₁ = 2 × 4 = 8

a₃ = 2a₂ = 2 × 8 = 16

a₄ = 2a₃ = 2 × 16 = 32

a₅ = 2a₄ = 2 × 32 = 64

7 0
2 years ago
What is 6+7 pleaes i ned help
IRISSAK [1]

Answer:

13

Step-by-step explanation:

you would count up 7 times from 6

8 0
3 years ago
Dilate by a scale<br> factor of 1/2<br> AL<br> D
Firdavs [7]

Answer:

The image triangle ΔD'L'W' after the dilation by a scale factor of 1/2 will have the vertices:

  • D' (0, 1)
  • L' (1/2, 5/2) or L'(0.5, 2.5)
  • W' (5/2, 2) or W'(2.5, 2)

`The figure of the dilated image is attached below.

Step-by-step explanation:

Given the triangle ΔDLW withe the vertices

  • D(0, 2)
  • L(1, 5)
  • W(5, 4)

As the scale factor 1/2 < 0, thus the image triangle will be smaller than the original triangle.

The rule of dilation is given by

Dilation: (x, y)  →  (1/2x, 1/2y), centered at (0, 0)

D(0, 2)  → D' (1/2x, 1/2y) → D' (1/2(0), 1/2(2)) = D' (0, 1)

L(1, 5)  → L'(1/2x, 1/2y) →  L'(1/2(1), 1/2(5)) = L' (1/2, 5/2)

W(5, 4)  → W'(1/2x, 1/2y) →  W'(1/2(5), 1/2(4)) = W' (5/2, 2)

Therefore, the image triangle ΔD'L'W' after the dilation by a scale factor of 1/2 will have the vertices:

  • D' (0, 1)
  • L' (1/2, 5/2) or L'(0.5, 2.5)
  • W' (5/2, 2) or W'(2.5, 2)

`The figure of the dilated image is attached below.

7 0
3 years ago
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