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3 years ago

Alberto changes 800 Argentine pesos (ARS) into dollars (S) when the rate is S1 - 3.8235 ARS

Mathematics

1 answer:

KiRa [710]3 years ago

6 0

Answer:

Alberto now has 225.23 pesos

Step-by-step explanation:

800 (ARS) / 3.8235 = x(s)

x = 209.23 dollars (s)

209.23 dollars (s) - 150 dollars (s)

= 59.23 dollars (s)

59.23 * 3.8035 = 225.23 (ARS).

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Evaluate 15 + |-3| - 4

hichkok12 [17]

Answer:

Step-by-step explanation:

we are solving 15 + |-3| - 4

anything inside | | means it's absolute value.

absolute value means that even if it is a negative number inside, it will change to positive. if it is a positive number inside, it will stay the same.

so |-3| is 3.

15 + 3 - 4

18 - 4 = 14.

we got the answer

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3 years ago

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If you deposit $6000 into an account paying 8% annual interest compounded monthly, how much money will be in the account after 7

Leviafan [203]

Answer:

$10278

Step-by-step explanation:

Given data

P= $6000

R= 8%

T= 7 years

The compound interest formula is

A=P(1+r)^t

substitute

A=6000(1+0.08)^7

A=6000(1.08)^7

A=6000*1.713

A=$10278

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3 years ago

Four out of nine dogs weigh less than 20 pounds.

vodka [1.7K]

The answer is 0.444 repeating.

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3 years ago

A builder wants to build the bridge whose cross section is shown in the diagram. Two companies offer simple bids on building the

leva [86]

The length of the bridge is the distance from the beginning to the end.

The distance b between each beam is 9ft.

Let:

$I \to$ I-Beam

$d_I \to$ distance between I beam and the bridge

$b \to$ distance between each I beam

Given that:

$I = \frac 34 ft\\$

$d_I = 3 ft$

$Length = 55ft\ 6in$ --- length of the bridge

From the diagram (see attachment), there are: 6 I-beams.

So, the length of the 6 I-beams is:

$L_1 = 6 \times I$

$L_1 = 6 \times \frac 34$

$L_1 = \frac {18}4$

$L_1 = 4.5ft$

There are 2 I-beams beside the bridge

So, the distance between the 2 I-beams and the bridge is:

$d_1 =2 \times d_I$

$d_1 =2 \times 3ft$

$d_1 =6ft$

There are 5 spaces between the I-beams

So, the length of the total spaces is:

$L_2 = 5 \times b$

$L_2 = 5b$

The total length is:

$Length = L_1 + d_1 + L_2$

So, we have:

$4.5ft + 6ft + 5b = 55ft\ 6in$

Collect like terms

$5b = 55ft\ 6in - 4.5ft - 6ft$

$5b = 44.5ft\ 6in$

Convert inches to feet

$5b = 44.5ft\ + \frac{6}{12}ft$

$5b = 44.5ft\ + 0.5ft$

$5b = 45ft$

Divide both sides by 5

$b = 9ft$

Hence, the distance (b) between each beam is 9ft.