Answer:
4 tiles
Step-by-step explanation:
4/1 = 4
The total area of the room is 37.6376 and the no. of cans required to paint the wall is 3 cans.
The measurement of two of the walls is 2.86 metres and 3.16 metre
Area of the two walls = 2(length x breadth)
Area = 2(2.86 x 3.16) = 18.0752 m²
The measurement of the other two walls is 2.86 metres and 3.42 metres
Area of the two walls = 2(length × breadth)
Area = 2(2.86 × 3.42) = 19.5624 m²
Total area = 18.0752 + 19.5624 = 37.6376 m²
If one can of paint can cover 15 m², the no. of cans required to paint the bedroom will be
No. of cans = Total area/Area covered by one can of paint
No. of cans = 37.6376/15 = 2.5091 = 3 cans (approx.)
Answer:
5/12
Step-by-step explanation:
You have to make it a common denomator and then subract until equeal.
Answer:
Step-by-step explanation:
We have been given two expressions 
and
Now we need to find out least common multiple of these two expressions.
First we need to find out what is common factor of both expressions. and
Least common multiple means find the expression which can be divided by both expressions.
15 and 6 both goes into 30
so 30 is part of LCM (least common multiple )
Now pickup the highest exponent of each variable.
So we get 
Hence required least common multiple is
