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kodGreya [7K]
3 years ago
11

a pizza place sells pizzas for $7 each plus a $4 delivery charge per order. if pat orders 3 pizzas to be delivered, what will be

his total cost?
Mathematics
1 answer:
Novosadov [1.4K]3 years ago
4 0
The total order would be $33. Because you would first add up the $7 for the pizza 3 times. Then, you would add up the $4 for delivery 3 times. So you would get 21+12=33.
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What is the expirimental probability of rolling a number greater than 4
Ivenika [448]

Answer:

36

Then the experimental probability of rolling a number greater than four would be 36 or one-half. As the number of trials increases, the experimental probability will become close to the theoretical probability.

5 0
3 years ago
A single tree produces about 2.6 × 10² lb of oxygen each year. The Amazon rainforest has about 3.9 X 10^11 trees.
Ymorist [56]
(2.6\times10^2) \times (3.9\times10^{11}) = 1.014\times10^{14}

1.014\times10^{14} <---How much is produced by all the trees in a year. 
They want how much each day so divide by 365


\frac{1.014\times10^{14}}{365} = 2.77808\times10^{11}
2.77808\times10^{11} <---answer per day

6 0
3 years ago
Read 2 more answers
Whats the answer???​
Nookie1986 [14]

Answer:

35 I think

Step-by-step explanation:

8 0
3 years ago
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Each morning librarians place 560 books on a book shelf in the school library. Each student that visits library that day takes e
Alex73 [517]

Answer:

Step-by-step explanation:

560=3s+b

b.

560=3×150+b

b=560-450=110

when s=149,b=560-3×149=560-447=113

s=2,b=560-3×2=560-6=554

s=1,b=560-3×1=557

s=0,b=560-3×o=560

so domain of b={110,113,116,...,554,557,560}

7 0
3 years ago
At a university, 60% of the 7,400 students are female. The student newspaper reports the results of a survey of a random sample
omeli [17]

Given Information:

Population mean = p  = 60% = 0.60

Population size = N = 7400

Sample size = n = 50

Required Information:

Sample mean = μ = ?

standard deviation = σ = ?

Answer:

Sample mean = μ = 0.60

standard deviation = σ = 0.069

Step-by-step explanation:

We know from the central limit theorem, the sampling distribution is approximately normal as long as the expected number of successes and failures are equal or greater than 10

np ≥ 10

50*0.60 ≥ 10

30 ≥ 10 (satisfied)

n(1 - p) ≥ 10

50(1 - 0.60) ≥ 10

50(0.40) ≥ 10

20 ≥ 10  (satisfied)

The mean of the sampling distribution will be same as population mean that is

Sample mean = p = μ = 0.60

The standard deviation for this sampling distribution is given by

\sigma = \sqrt{\frac{p(1-p)}{n} }

Where p is the population mean that is proportion of female students and n is the sample size.

\sigma = \sqrt{\frac{0.60(1-0.60)}{50} }\\\\\sigma = \sqrt{\frac{0.60(0.40)}{50} }\\\\\sigma = \sqrt{\frac{0.24}{50} }\\\\\sigma = \sqrt{0.0048} }\\\\\sigma =  0.069

Therefore, the standard deviation of the sampling distribution is 0.069.

4 0
3 years ago
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