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pychu [463]
3 years ago
6

The Carry-on Luggage Company must set up an assembly line for a wheeled carry-on bag. Forecasts show that 60 units per hour shou

ld be produced. The tasks required, task times, and precedence relationships are as follows:
TaskTime (seconds) Predecessors
A 30 -
B 50 A
C 25 A
D 10 B
E 25 B
F 15 B
G 10 C ,E ,F
H 30 D, G
a. Draw the precedence diagram.
b. What is the takt time?
c. What is the theoretical number of workstations?
d. Assign the tasks to the workstations to balance the line using the longest operating time rule.
e. What is the efficiency of the balanced line?

Business
1 answer:
Diano4ka-milaya [45]3 years ago
4 0

Answer:

a. See attachment below

b. 60 seconds per unit

c. 4 workstations

d. See attachment below

e. Efficiency = 81.25%

Explanation:

b.

Time required = 60 units per hour

Task time = Time required to for production per units

Since 1 hour is required for 60 units and there are 3600 seconds in one hour (60 * 60)

This is calculated by.

3600seconds/60 units

= 60 seconds per unit

c. Theoretical Number of workstations is calculated by:

Total Time Taken/Task Time

=(30 + 50 + 25 + 10 + 25 + 15 + 10 + 30)/60

= 195/60

= 3.25

This is round up to 4 workstations

d. See Attachment Below

e. Efficiency is calculated as:

(Total Time Taken)/ (Theoretical Workstations * Task Time)

= 195/(4 * 60)

= 195/240

= 0.8125

= 81.25%

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Answer:

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4 years ago
Read 2 more answers
A consumer's weekly income is $300 and the consumer buys 5 bars of chocolate per week. When income increases to $330, the consum
ioda

Answer:

The correct answer is option E.

Explanation:

Income elasticity of demand measures the change in quantity demanded of a product because of a change in the income of the consumer. It is calculated as a ratio of change in quantity demanded and change in income.  

At the income level of $300, the consumers buy 5 bars of chocolate. When the income increases to $330, the consumer buys 6 bars of chocolate.  

The income elasticity of demand is  

= \frac{\Delta Q}{\Delta Y}

= \frac{\frac{6-5}{5} }{\frac{330-300}{300} }

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= \frac{0.2}{0.1}

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