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stellarik [79]
3 years ago
13

What are some of the criticisms against GM foods?

Advanced Placement (AP)
2 answers:
Lapatulllka [165]3 years ago
7 0

Answer:

the genes have been modified and switched. it can have unknown side effects and harms wild life

Explanation:

hope this helps

Bingel [31]3 years ago
5 0

If by GM you mean genetically modified, here's my answer


It can cause many health problems, and foods with gmo often have misleading labels not telling that the are GM.


Hope this helps!

Plz mark Brainliest

- Courtney

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Compare and Contrast- What is a felony? What is a misdemeanor? Explain how punishments for crimes differ based on their classifi
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Hi MarvinTorres118!


Questions:


What is a felony?


What is a misdemeanor?


Explain how punishments for crimes differ based on their classification (felony or misdemeanor).


Answers:


Felony - is a crime that usually involves violence. This punishment is usually 1 or more years in prison or by death.


Misdemeanor - is a simple wrong doing that dosent result in very punishible events.


Felonies are more of a punishment than misdemeanors are. For example a felony you can kill someone and got to jail are get killed. A misdeameanor for example is just like getting banned or suspended from something.


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What role did Alexander Hamilton play in the election of 1800?
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Election the civil war
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The regions bounded by the graphs of y=x2 and y=sin2x are shaded in the figure above. What is the sum of the areas of the shaded
Alex Ar [27]

Answer:

The sum of the area of the shaded regions = 0.248685

Explanation:

The sum of the area of the shaded region is given as follows;

The point of intersection of the graphs are;

y = x/2

y = sin²x

∴ At the intersection, x/2 = sin²x

sinx = √(x/2)

Using Microsoft Excel, or Wolfram Alpha, we have that the possible solutions to the above equation are;

x = 0, x ≈ 0.55 or x ≈ 1.85

The area under the line y = x/2, between the points x = 0 and x ≈ 0.55, A₁, is given as follows

1/2 × (0.55)×0.55/2 ≈ 0.075625

The area under the line y = sin²x, between the points x = 0 and x ≈ 0.55, A₂, is given using as follows;

\int\limits {sin^n(x)} \, dx = -\dfrac{1}{n} sin^{n-1}(x) \cdot cos(x) + \dfrac{n-1}{n} \int\limits {sin^{n-2}(x)} \, dx

Therefore;

A_2 = \int\limits^{0.55}_0 {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_0 ^{0.55}

∴ A₂ =1/2 × ((0.55 - sin(0.55)×cos(0.55)) - (0 - sin(0)×cos(0)) ≈ 0.0522

The shaded area, A_{1 shaded} = A₁ - A₂ = 0.075625 - 0.0522 ≈ 0.023425

Similarly, we have, between points 0.55 and 1.85

A₃ = 1/2 × (1.85 - 0.55) × 1/2 × (1.85 - 0.55) + (1.85 - 0.55) × 0.55/2 = 0.78

For y = sin²x, we have;

A_4 = \int\limits^{1.85}_{0.55} {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_{0.55} ^{1.85} \approx 1.00526

The shaded area, A_{2 shaded} = A₄ - A₃ = 1.00526 - 0.78 ≈ 0.22526

The sum of the area of the shaded regions, ∑A = A_{1 shaded} + A_{2 shaded}

∴ A = 0.023425 + 0.22526 = 0.248685

The sum of the area of the shaded regions, ∑A = 0.248685

8 0
3 years ago
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