1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Andrew [12]
3 years ago
8

1760 is compounded daily at a rate of 6% for 7 years

Mathematics
1 answer:
dlinn [17]3 years ago
3 0

Principal amount is $1510, so P = 1,760 dollars.

Compounding period is daily, so N = 365.

Interest rate is 6%, so r = 0.06

Time of investment is 7 years, so t = 7 years.

We can use compound interest formula as given below :-

Amount = P*(1+\frac{r}{N} )^{(N*t)}

Amount=1760*(1+\frac{0.06}{365} )^{(365*7)} \\\\
Amount=1760*(1+0.000164384)^{(2555)} \\\\
Amount=1760*(1.000164384 )^{(2555)} \\\\
Amount=1760*(1.521909017) \\\\
Amount=2678.55987 \approx 2678.56 \;dollars

Hence, total amount in account would be 2,678.56 dollars.

You might be interested in
Identify the stem: 556 <br> A. 5<br> B. 6<br> C. 55<br> D. 56<br> ...Ahem.. Help?
Semenov [28]
C. a leaf is only one digit
3 0
3 years ago
Read 2 more answers
What is the slope of PV?
vagabundo [1.1K]
Not sure but It should be -4/1
5 0
3 years ago
Write the number white the same value as 32
frutty [35]
I think the answer is
0.32
7 0
3 years ago
There are (4^9)5 ⋅ 4^0 books at the library. What is the total number of books at the library? 4^9 - 4^45 - 4^46 - 1
maria [59]
Exponent rules : (a^m)^n = a^(mn) and a^0 = 1

(4^9)^5 * 4^0 =
4^45 * 1 =
4^45 <==
7 0
3 years ago
Suppose you are investigating the relationship between two variables, traffic flow and expected lead content, where traffic flow
prisoha [69]

Answer:

The answers is " Option B".

Step-by-step explanation:

CI=\hat{Y}\pm t_{Critical}\times S_{e}

Where,

\hat{Y}= predicted value of lead content when traffic flow is 15.

\to df=n-1=8-1=7

 95\% \ CI\  is\  (463.5, 596.3) \\\\\hat{Y}=\frac{(463.5+596.3)}{2}\\\\

     =\frac{1059.8}{2}\\\\=529.9

Calculating thet-critical valuet_{ \{\frac{\alpha}{2},\ df \}}=-2.365

The lower predicted value =529.9-2.365(Se)

463.5=529.9-2.365(Se)\\\\529.9-463.5=2.365(Se)\\\\66.4=2.365(Se)\\\\Se=\frac{66.4}{2.365} \\\\Se=28.076

When 99\% of CI use as the expected lead content: \to 529.9\pm t_{0.005,7}\times 28.076 \\\\=(529.9 \pm 3.499 \times 28.076)\\\\=(529.9 \pm 98.238)\\\\=(529.9-98.238, 529.9+98.238)\\\\=(431.662, 628.138)\\\\=(431.6, 628.1)

8 0
3 years ago
Other questions:
  • Solve for the variable x^2 - 8 = -1 Show all work please
    10·1 answer
  • A ticket to a movie theatre for a student is $7. The cost for an adult is $2 more than for a student. How much would it cost 13
    11·1 answer
  • You are repairing a fence and have 7.9 metres of wood. You need 10 metres.
    7·1 answer
  • Write this number in standard notation.<br> 1.986 x 106
    14·1 answer
  • What is the inverse of the following function?<br><br> y = 1/2x −6
    5·1 answer
  • Someone please help me with this
    14·1 answer
  • Solve for an angle in right triangles
    6·1 answer
  • Use the original price and the markup to find the retail price.
    14·1 answer
  • Write an integer to describe the situation AND explain the meaning of zero. 35 FEET BELOW SEA LEVEL
    14·1 answer
  • Find (fog)(x) and (gof)(x) f(x) = 8x-5, g(x) = 10 - 2x<br><br><br><br><br>help please ​
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!