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Andrew [12]
3 years ago
8

1760 is compounded daily at a rate of 6% for 7 years

Mathematics
1 answer:
dlinn [17]3 years ago
3 0

Principal amount is $1510, so P = 1,760 dollars.

Compounding period is daily, so N = 365.

Interest rate is 6%, so r = 0.06

Time of investment is 7 years, so t = 7 years.

We can use compound interest formula as given below :-

Amount = P*(1+\frac{r}{N} )^{(N*t)}

Amount=1760*(1+\frac{0.06}{365} )^{(365*7)} \\\\
Amount=1760*(1+0.000164384)^{(2555)} \\\\
Amount=1760*(1.000164384 )^{(2555)} \\\\
Amount=1760*(1.521909017) \\\\
Amount=2678.55987 \approx 2678.56 \;dollars

Hence, total amount in account would be 2,678.56 dollars.

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Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the data and then​ (e) answer the given question. Listed below
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Answer:

a) \bar X = 369.62

b) Median=175

c) Mode =450

With a frequency of 4

d) MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

<u>e)</u>s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

Step-by-step explanation:

We have the following data set given:

49 70 70 70 75 75 85 95 100 125 150 150 175 184 225 225 275 350 400 450 450 450 450 1500 3000

Part a

The mean can be calculated with this formula:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

Replacing we got:

\bar X = 369.62

Part b

Since the sample size is n =25 we can calculate the median from the dataset ordered on increasing way. And for this case the median would be the value in the 13th position and we got:

Median=175

Part c

The mode is the most repeated value in the sample and for this case is:

Mode =450

With a frequency of 4

Part d

The midrange for this case is defined as:

MidR= \frac{Max +Min}{2}= \frac{49+3000}{2}= 1524.5

Part e

For this case we can calculate the deviation given by:

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

And replacing we got:

s = 621.76

And we can find the limits without any outliers using two deviations from the mean and we got:

\bar X+2\sigma = 369.62 +2*621.76 = 1361

And for this case we have two values above the upper limit so then we can conclude that 1500 and 3000 are potential outliers for this case

5 0
3 years ago
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