Ask question

Ask question

All categories

3 years ago

14

Use the original price and the markup to find the retail price.

1 answer:

Natasha_Volkova [10]3 years ago

4 0

41 dollarsStep-by-step explanation:

You might be interested in

Write the equation y = -(x – 5)2 + 21 in standard form.

GuDViN [60]

Answer:

y = − x + 31

Step-by-step explanation:

y = − 2 x + 31

5 0

2 years ago

2 x + y equals negative 9

Vilka [71]

Answer:

The given equation which is in two variable is

⇒2 x + y =9

As we know that to get a unique solution you need two intersecting lines.

But here only one line is given.

On a single line there lie infinite number of points.

So, for different values of x we get different values of y or different values of y we get different values of x.

So , we can write the above equation as

either ⇒y=9-2 x Or x=9-2 y

I have drawn graph for you.

Thus , there are infinite number of solution of this equation. Like (0,9),(1,7),(2,5),(-2,13),(-1,11),(-3,15)......

6 0

3 years ago

PLEASE HELP ASAP

Crank

Option D: $f(x)=-2(x+2)(x-4)$ is the function

Explanation:

Let the general form of quadratic equation be $y=a x^{2}+b x+c$

The function passes through the intercepts $(-2,0)$ and $(4,0)$ and also passes though the point $(-1,10)$

Substituting the points $(-2,0)$ , $(4,0)$ and $(-1,10)$ in the equation $y=a x^{2}+b x+c$ , we get,

$4a -2b+c=0$ -----------(1)

$16a +4b+c=0$ ----------(2)

$a-b+c=10$ -----------(3)

Subtracting (1) and (2), we get,

$\ \ 4a -2b+c=0\\ 16a +4b+c=0\\\---------\\ \ \ -12a-6b=0$ -----------(4)

Subtracting (2) and (3), we get,

$16a +4b+c=0\\\ \ a \ \ - \ \ b \ +c=10\\---------\\15a+5b=-10$ ------------(5)

Multiplying equation (4) by 5 and equation (5) by 4, to cancel the term b when adding, we get,

$-60a-30b=0\\\ 90a+30b=-60\\--------\\30a=-60\\\ \ a=-2$

Thus, the value of a is $a=-2$

Substituting $a=-2$ in equation (4), we get,

$\begin{aligned}-12 a+6 b &=0 \\-12(-2)-6 b &=0 \\ 24-6 b &=0 \\ 24 &=6 b \\ 4 &=b \end{aligned}$

Thus, the value of b is $b=4$

Now, substituting the value of a and b in equation (1), we have,

$\begin{aligned} 4 a-2 b+c &=0 \\ 4(-2)-2(4)+c &=0 \\-8-8+c &=0 \\ c &=16 \end{aligned}$

Thus, the value of c is $c=16$

Now, substituting the value of a,b and c in the general formula $y=a x^{2}+b x+c$ , we get,

$y=-2x^{2} +4x+16$

Taking out the common term as -2 we get,

$y=-2(x^{2} -2x-8)$

Factoring , we get,

$y=-2(x+2)(x-4)$

Thus, the function is $f(x)=-2(x+2)(x-4)$

7 0

3 years ago

If x and y are two rational numbers such that x < y , then ______ is a rational number in between x and y.

stich3 [128]

Answer:

$\dfrac{x+y}{2}$

Step-by-step explanation:

Let first number be x and another number is y.

A rational number is a fraction that can be expressed in the form of x/y.

A rational number between x and y is given by :

$R=\dfrac{x+y}{2}$

So,

If x and y are two rational numbers such that x < y , then $\dfrac{x+y}{2}$ is a rational number in between x and y.

3 0

2 years ago

What's 149 rounded to the nearest tenth

alexandr1967 [171]

150 because you round the 4 because the number in the ones place is over 5.

3 0

3 years ago