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Vlada [557]
3 years ago
13

In the formula C= 2πr c stands for

Mathematics
1 answer:
Stolb23 [73]3 years ago
3 0
Circumference (of a circle)

You find a circumference by this:

C- circumference
= - equals
2-2
π- pi
R- radius


Hope this helps :)
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20 POINTS! Please look at the attached image!
Ira Lisetskai [31]

Answer:

a) 5^4 / 5^2, 5^2

b) 7^3 /  7^3, 7^0=1

c) 8^7/8^4, 8^3

Step-by-step explanation:

A quotient of two powers is basically the powers before its simplified. So for a 5 x 5 x 5 x 5 is 5 being multiplied by itself 4 times divided by 5 x 5 which is 5 being multiplied by itself 2 times. So this leads us to the conclusion that 5^4/5^2 for the quotient of two powers. Then using the rules of powers when dividing powers you subtract so in this case 4-2 is 2. So the answer is 5^2 for single power. The other problems are basically the same as well, just different numbers.

b) (7 x 7 x 7)/ (7 x 7 x 7)= 7^3/7^3=7^0=1

c)(8 x 8 x 8 x 8 x 8 x 8 x 8)/(8 x 8 x 8 x 8)= 8^7/8^4= 8^3

8 0
3 years ago
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emmasim [6.3K]
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4 0
3 years ago
What is the product of 76 and 6.0 x 10^2 expressed in scientific notation?
Dima020 [189]

Answer:

45.6 x 10^3

Step-by-step explanation:

76 can be expressed as 7.6 x 10^1.

Now, you can multiply the two values together.

7.6 x 6.0 is 45.6.

Then, add the two exponents together:

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8 0
2 years ago
What was the equation of the graph below before it was shifted to the right 1 unit? (equation was g(x)=(x-1.5)^3-(x-1.5))
harina [27]
If graph of the function y=f(x) was shifted to the  right 1 unit, then you got new function y=f(x-1).
Reversly, if you have the function g(x)=(x-1.5)^3-(x-1.5) that is obtained by shifting to the right 1 unit, then the initial function was

g(x+1)=(x+1-1.5)^3-(x+1-1.5), \\ g(x+1)=(x-0.5)^3-(x-0.5).
Answer: Correct choice is D.
3 0
3 years ago
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For which function is f(x) equal to f-1(x)?
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C...to show this, interchange letters: x = (y+1)/(y-1)xy-x = y + 1xy - y) = x + 1y(x-1) = x+1y = (x+1)/(x-1) ⇐ this is f-1(x) and it's identical to f(x).  Note: <span>the equal sign is missing in the definitions of the functions c. & d.</span>
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3 years ago
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