Since AED forms a straight line, all involved angles sum to 180°. Therefore AEB + BED = 180. Also, since EC bisects BED, BEC = CED, and BED = 2× CED. Now to substitute the first equation: AEB + BED = 180 AEB + 2×CED = 180 11x-12 + 2(4x+1) = 180 11x-12+8x+2 = 180 19x-10 = 180 19x-10+10 = 180+10 19x = 190 x = 10 So what is m<AEC?? It is the sum of AEB + BEC, and since BEC = CED we can say that: AEC = AEB + CED AEC = 11x-12 + 4x+1 = 15x-11 = 15(10)-11 = 150-11 m<AEC = 139°