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4 years ago

When 8 is subtracted from a certain number and the result is multiplied by 3 the answer is 21. What is the original number?

1 answer:

5 0

The original number is 15.

Let’s work it out.

First, divide.

21 divided by 3 is 7.

Now, add.

8 + 7 = 15

This is true because...

15 - 8 = 7

Hope this helps, have a great day, stay safe and positive.

:)

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Please! due in 1 hour! thanks!

8_murik_8 [283]

Answer:

Well $y =ax^2 + bx + c$, = -3. $/$

Step-by-step explanation:

8 0

3 years ago

Plz Help, and solve. Show your work. I will give Brainliest. A - 7 = -13 solve and show your work 10X - 8 = 9X + 8 Can a right t

likoan [24]

Answer:

A - 7 = -13

Add 7

A = -6

10X - 8 = 9X + 8

Add 8

10X = 9X + 16

Subtract 9X

X = 16

In a right triangle, where a and b are the shorter sides, and c is the longer side a^2+b^2=c^2

Thus, plug in the values.

12^2+16^2=20^2

144+256=400

400=400.

Because the equation is true, 12, 16, and 20 can be a right triangle

<em>Hope it helps <3</em>

3 0

4 years ago

Read 2 more answers

A farmer has 32 cows. he puts an equal number of cows in 4 fields. each cow produces 6 gallons of milk. how much milk do the cow

garri49 [273]

Answer:

48/field

you take 32÷4=8 and then you 8*6=48 each field

4 0

2 years ago

Calculate the limit of the function with L'Hospital rule

mr_godi [17]

Answer:

L=24

Step-by-step explanation:

L'Hopital's Rule for Evaluating Limits:

Rule is that if $\lim_{x \to a} \frac{f(x)}{g(x)}$ takes $\frac{0}{0}$ or $\frac{\infty}{\infty}$ form, then,

$\lim_{x \to a} \frac{f(x)}{g(x)}= \lim_{x \to a} \frac{f'(x)}{g'(x)}$

where $f'(x)=\frac{df(x)}{dx}$ and $g'(x)=\frac{dg(x)}{dx}$

Now coming to the problem,

$L= \lim_{x \to \frac{\pi}{6} } \frac{cot^{3}x-3cotx}{cos(x+\frac{\pi}{3} )}$

Here $f(x)=cot^{3}x-3cotx$ and $g(x)=cos(x+\frac{\pi}{3} )$

Substituting $x=\frac{\pi}{6}$ in f(x) and g(x),

$f(\frac{\pi}{6})=cot^{3}\frac{\pi}{6}-3cot\frac{\pi}{6}\\=3\sqrt{3}-3\sqrt{3}\\ =0$

$g(\frac{\pi}{6})=cos(\frac{\pi}{6}+\frac{\pi}{3})\\=cos\frac{\pi}{2}\\=0$

Since L takes the form $\frac{0}{0}$ , using l'hopital's rule

$L= \lim_{x \to \frac{\pi}{6}} \frac{cot^{3}x-3cotx}{cos(x+\frac{\pi}{3})}= \lim_{x \to \frac{\pi}{6}} \frac{3cot^{2}x(-cosec^{2}x)-3(-cosec^{2}x)}{-sin(x+\frac{\pi}{3})}$

now substituting $x=\frac{\pi}{6}$ ,

$L= \lim_{x \to \frac{\pi}{6}} \frac{3cot^{2}\frac{\pi}{6}(-cosec^{2}\frac{\pi}{6})-3(-cosec^{2}\frac{\pi}{6})}{-sin(\frac{\pi}{6}+\frac{\pi}{3})}\\=\frac{3*3^{2}(-2^{2})+3(2^{2})}{-1}\\=24$

6 0

3 years ago

Ok need help please help Thank you

Step2247 [10]

96 1/2

there is ur answer i think :)

7 0

3 years ago

When 8 is subtracted from a certain number and the result is multiplied by 3 the answer is 21. What is the original number?​

When 8 is subtracted from a certain number and the result is multiplied by 3 the answer is 21. What is the original number?