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4 years ago

Give a example of term in math

Mathematics

1 answer:

Viefleur [7K]4 years ago

5 0

7x or just x

Both of them are terms when they have a variable next to it

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A fish tank has a length of 14cm, a width of 25cm, and a height of 15cm. It is only filled with water up to a height of 7 centim

bazaltina [42]

Answer:

2800 cm^3, or 2.8 liters

Step-by-step explanation:

The base of the tank remains 14 cm × 25 cm. The remaining height is 15 -7 = 8 cm, so the remaining volume is ...

(14 cm)(25 cm)(8 cm) = 2800 cm^3 = 2.8 liters

_____

1 liter = 1000 cm^3

4 0

4 years ago

X2–6x + 10 is to be written in the form ( x +a)2+ b Find the values of a and b.

vampirchik [111]

Answer:

a = -3 and b = 1

Step-by-step explanation:

x² - 6x + 10

→ Half the second term and place it in the bracket

( x - 3 )²

→ Square -3

- ( 3 )² = -9

→ Place this outside the brackets along with plus 10

( x - 3 ) ² - 9 + 10

→ Simplify

( x - 3 ) ² + 1

8 0

3 years ago

2. Harry just deposited $1500 into a savings account giving 6% interest compounded quarterly.a) How much will be in the account

Studentka2010 [4]

The formula for compound interest is:

$\begin{gathered} A=P(1+\frac{r}{n})^{nt} \\ \text{where,} \\ A=\text{ Final amount} \\ r=\text{ Interest rate} \\ n=\text{ Number of times interest applied per period} \\ t=\text{ Number of time period elapsed} \\ P=\text{ Intial principal balance} \end{gathered}$

Given data:

$\begin{gathered} P=\text{ \$1500} \\ r=6\text{ \%}=0.06 \\ n=4\text{ times (compounded quarterly)} \end{gathered}$

a. After ten years, that is t = 10 years, the amount in the account will be

$\begin{gathered} A=1500(1+\frac{0.06}{4})^{4\times10} \\ A=\text{ }1500(1+0.015)^{40} \\ A=\text{ }1500(1.015)^{40} \\ A=\text{ \$2721.03} \end{gathered}$

b. After twenty years, that is t = 20 years, the amount in the account will be:

$\begin{gathered} A=1500(1+\frac{0.06}{4})^{4\times20} \\ A=1500(1.015)^{4\times20} \\ A=1500(1.015)^{80} \\ A=\text{ \$}4935.99 \end{gathered}$

c. The time it takes for Harry's initial account value to double will be:

$\begin{gathered} A=2\text{ x initial value = 2 }\times\text{ \$1500 = \$3000} \\ 3000=1500(1.015)^{4t} \\ (1.015)^{4t}=\frac{3000}{1500} \\ (1.015)^{4t}=2 \\ \text{ Find the logarithm of both sides} \\ \ln (1.015)^{4t}=\ln 2 \\ 4t=\frac{\ln 2}{\ln 1.015} \\ 4t=46.56 \\ t=\frac{46.56}{4}=11.64 \end{gathered}$

Therefore, the time it takes Harry's initial account to double is approximately 11 years

8 0

1 year ago

Which shows the correct substitution of the values a, b, and c from the equation –2 = –x + x2 – 4 into the quadratic formula?

Serhud [2]

X=[-(-1)+or-sqrt ((-1)^2-4x1x-2)]/(2x1)