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pishuonlain [190]
4 years ago
13

What is a not helpful high friction

Chemistry
1 answer:
Setler [38]4 years ago
5 0
I think higher friction cause change in body temperature and can cause fire
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Compare the boiling points of 1-pentyne and 1-octyne. Compare the vapor pressure curves of 1-butene and 1-heptene.
soldi70 [24.7K]
1-pentyne  boiling point is 40 degrees C it is lower than the one for 1-octyne which is 126 degrees C the vapor pressure for 1-butene is higher at low temperatures than 1-heptene.These are due to the difference in the length of the chains.  The strong molecular forces are stronger in large molecules.  There is more energy needed to move large molecules to the vapor phase when in liquid form.

7 0
3 years ago
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How many grams are in 9.8 moles of calcium
FrozenT [24]

Answer:

0.24 Moles i believe

Explanation:

5 0
3 years ago
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Which of the following is a helpful addition to your observations?
Pavlova-9 [17]
The answer to that question would be C
3 0
3 years ago
How many mL of 0.100 M NaCl would be required to make a 0.0365 M solution of NaCl when diluted to 150.0 mL with water?
Tatiana [17]

Answer:

54.75 mL

Explanation:

First calculate the number of moles of NaCl in the 150mL solution of NaCl

0.0365 moles should be present on 1000cm3 or 1dm3 of water.

1L = 1 dm3

1 mL = 1 / 1000 dm3

150 mL = 150/1000 dm3 = 0.15 dm3

If x moles are present in 0.15 dm3,

x/ 0.15 = 0.0365

We get x= 0.0365 × 0.15 mol

Now x amount of moles should be taken from the initial 0.100 M NaCl solution

So 0.1 moldm-3 = 0.0365× 0.15 mol / V

we get V = 0.05475 dm3

V= 0.05475 L

V= 54.75 mL

3 0
3 years ago
What is the molarity of an HCl solution if 37.0 mL is completely titrated by 56.0 mL of an NaOH solution whose concentration is
Nata [24]

Answer:

Option A. 0.378M

Explanation:

Data obtained from the question include:

Molarity of acid (Ma) =..?

Volume of acid (Va) = 37.0 mL

Volume of base (Vb) = 56.0 mL

Molarity of base (Mb) = 0.250 M

Next, we shall write the balanced equation for the reaction. This is given below:

HCl + NaOH —> NaCl + H2O

From the balanced equation above,

The mole ratio of the acid (nA) = 1

The mole ratio of the base (nB) = 1

Finally, we can determine the molarity of the acid as shown below :

MaVa/MbVb = nA/nB

Ma x 37 / 0.25 x 56 = 1

Cross multiply

Ma x 37 = 0.25 x 56

Divide both side by 37

Ma = 0.25 x 56 /37

Ma = 0.378M

Therefore, the molarity of the acid, HCl is 0.378M

5 0
4 years ago
Read 2 more answers
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