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4 years ago

What is a not helpful high friction

Chemistry

1 answer:

Setler [38]4 years ago

5 0

I think higher friction cause change in body temperature and can cause fire

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7 g of common salt is kept in water in a dish and the dish is

SVETLANKA909090 [29]

I would go with 9g as well but if i’m wrong sorry much love

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3 years ago

what coefficients must be added to balance the following reaction ? ___ Li + ___ H3 PO4 yields ___ H2 + Li3 PO4

nataly862011 [7]

6Li+2H3PO4yields 3H2+2Li3PO4

7 0

3 years ago

Hydrogen peroxide decomposes to water and oxygen at constant pressure by the following reaction: 2H2O2(l) → 2H2O(l) + O2(g) ΔH =

Mashcka [7]

<u>Answer:</u> The amount of heat released is -7.203 kJ

<u>Explanation:</u>

The given chemical equation follows:

$2H_2O_2(l)\rightarrow 2H_2O(l )+O_2(g);\Delta H=-196kJ$

To calculate the enthalpy change for 1 mole of the hydrogen peroxide, we use unitary method:

When 2 moles of hydrogen peroxide is reacted, the enthalpy of the reaction is -196 kJ

So, when 1 mole of hydrogen peroxide will react, the enthalpy of the reaction will be $\frac{-196}{2}\times 1=-98kJ$

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Given mass of hydrogen peroxide = 2.50 g

Molar mass of hydrogen peroxide = 34 g/mol

Putting values in above equation, we get:

$\text{Moles of hydrogen peroxide}=\frac{2.50g}{34g/mol}=0.0735mol$

To calculate the heat of the reaction, we use the equation:

$\Delta H_{rxn}=\frac{q}{n}$

where,

$q$ = amount of heat released

n = number of moles = 0.0735 moles

$\Delta H_{rxn}$ = enthalpy change of the reaction = -98 kJ/mol

Putting values in above equation, we get:

$-98kJ/mol=\frac{q}{0.0735mol}\\\\q=(-98kJ/mol\times 0.0735mol)=-7.203kJ$

Hence, the amount of heat released is -7.203 kJ

8 0

4 years ago

From the chair conformation, rotate about the carbon-carbon bonds of the ring to form a boat conformation. In the boat conformat

pychu [463]

Is there a graph? I need to see one

5 0

3 years ago

How many grams of carbon are in 288.2 g of carbon tetrachloride?

xxMikexx [17]

Answer:

22.48 grams

Explanation:

Lets calculate the number of moles of CCl4 in 288.2 grams

Molar mass of CCl4 = 153.82 g/mol

mass % of carbon = 12 *100 / 153.82 = 7.8%

Hence, we can say that 7.8% of 288.2 grams is the mass of carbon

So, (7.8 * 288.2) / 100 = Mass of Carbon

Mass of carbon = 22.48 grams of carbon

3 0

3 years ago

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