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Rufina [12.5K]
3 years ago
5

How many grams are in 9.8 moles of calcium

Chemistry
2 answers:
saveliy_v [14]3 years ago
6 0
0.24 moles .
hope that helps.
FrozenT [24]3 years ago
5 0

Answer:

0.24 Moles i believe

Explanation:

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What is the mass of NaCl required to make 160 grams of a 12% solution of NaCl in water?
Ksivusya [100]

Answer:

0.5

L solution

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required molarity

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2.5 moles NaCl

1

L solution

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1.25 moles NaCl

Now, to convert this to grams of sodium chloride, you must use the mass of

1

mole of this compound as a conversion factor. The mass of

1

mole of sodium chloride is given by its molar mass

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moles NaCl

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58.44 g

1

mole NaCl

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73 g

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Explanation: if this is wrong i am very sorry

6 0
3 years ago
Why does scientists use atomic watch?​
Maru [420]

Answer:

atomic watch

Explanation:

it is used for the measurement of time.

6 0
2 years ago
Amanda found two snakes slithering in her garden. The first snake way only a baby,and was just 3/4 of an inch long. The second s
iren [92.7K]
To solve this problem you would add 3/4 to 7 1/3. 
3    22
4     3

9         88
12        12

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8 1/12
The final answer would be 8 and 1/12

7 0
3 years ago
Determine the mmol of both starting materials (factoring in that formic acid is not pure, but rather 88% weight/volume, or 88g/1
Oxana [17]

Solution :

Molecular      Molar Mass       Volume      Density       Mass      Moles      nmoles

formula            (g/mol)               (mL)          (g/mL)           (g)

$C_6H_8N_2$            108.14                                                    0.108      0.001          1

HCOOH           46.02                0.064          1.22     0.07808     0.0017       1.7

mmoles of o-phenylenediamine = 1 mmoles

mmoles of formic acid = 1.7 \approx 2 mmoles

From the reaction of o-phenylenediamine and formic acid, we see,

1 mmole of o-phenylenediamine reacts with 1 mmole of formic acid.

But here, 2 mmoles of the formic acid , this means that the formic acid is an excess reagent and the o-phenylenediamine is the limiting reagent here.

The amount of product depends on the limiting reagent that is o-phenylenediamine. So, 1mmole of o-phenylenediamine will give 1mmole of product.

molar mass of Benzimidazole = 118.14 g/mol

mmoles of Benzimidazole formed = 1 mmol

Mass of benzimidazole formed = molar mass x \frac{nmoles}{1000}

                                                    $=\frac{118.14 \times 1}{1000}$

                                                     = 0.11814 g

So the theoretical yield of Benzimidazole is = 0.118 g = 118mg

5 0
3 years ago
Can ya help me out real quick?
Taya2010 [7]

Answer:

302 kj heat is released by lowering the temperature

8 0
3 years ago
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