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stira [4]
3 years ago
14

Which of the following describes the end behavior of y = -x^2+bx+c as x approaches either positive or negative infinity?

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
5 0
The end behavior model of y is -x^2.
As x approaches either positive or neg infinity, -x^2 will always be negative.
Thus, "B) y approaches neg infinity" is the correct one. 
Hope that will help :))

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Simplify the expression please help
Mila [183]
Simplify the following:

((-1^3)/(-3)^(-3))^2

1^3 = 1:
((-1)/(-3)^(-3))^2

(-3)^(-3) = 1/(-1)^3×1/3^3 = (-1)/3^3:
((-1)/((-1)/3^3))^2

3^3 = 3×3^2:
((-1)/(-1/(3×3^2)))^2

3^2 = 9:
((-1)/((-1)/(3×9)))^2

3×9 = 27:
((-1)/((-1)/27))^2

Multiply the numerator of (-1)/((-1)/27) by the reciprocal of the denominator. (-1)/((-1)/27) = (-27)/(-1):
((-27)/(-1))^2

(-27)/(-1) = (-1)/(-1)×27 = 27:
27^2

 | 2 | 7
× | 2 | 7
1 | 8 | 9
5 | 4 | 0
7 | 2 | 9:
Answer:  729 = 1/729 thus c: is your Answer
3 0
3 years ago
What is the greatest three-digit multiple of 33 that can be written using three different digits?
tatuchka [14]

Answer:

I don't if this is right but is the 629

Step-by-step explanation:

8 0
3 years ago
Please Help I will reward Brainliest
Gennadij [26K]
The answer is 60 degrees angle
8 0
3 years ago
3m+n=10<br>5m-2n=2<br>what is the answer for this one ​
svlad2 [7]

Answer:

m = 2

n = 4

Step-by-step explanation:

Ok so to solve this, you want to get it so there is only one variable and then solve that equation. To do this, you can start by doing:

3m + n = 10

multiply both sides by 2

6m + 2n = 20

now, in both of your equations you have 2n so you can add the two equations:

6m + 2n = 20

+ 5m - 2n = 2

11m = 22

divide both sides by 11

m = 2.

Now, plug this value into the original equation, 3m + n = 10:

3 * 2 + n = 10

6 + n = 10

subtract 6 from both sides

n = 4

6 0
3 years ago
1. The midpoint of GH is (-2,3), and its endpoints are G (g,4) and H (-2,h). What are the values of g and h
alina1380 [7]

Answer:(g,h)=(-2,2)

Step-by-step explanation:

Given

Midpoint is (-2,3)

Endpoints are G(g,4) and H(-2,h)

Mid point of any two point is given by

x=\frac{x_1+x_2}{2}

and y=\frac{y_1+y_2}{2}

So,-2=\frac{g+(-2)}{2}

-4=g-2

g=-2

Also

3=\frac{4+h}{2}

6=4+h

h=2

Therefore (g,h)=(-2,2)

4 0
3 years ago
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