Choose all of the terms that best describe each of the sets of lines or points.

What is the range of the function y = x 2?

Leno4ka [110]

Answer:

$\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

The graph is also attached below.

Step-by-step explanation:

Given the function

$y=x^2$

We know that the range of a function is the set of values of the dependent variable for which a function is defined.

$\mathrm{For\:a\:parabola}\:ax^2+bx+c\:\mathrm{with\:Vertex}\:\left(x_v,\:y_v\right)$

$\mathrm{If}\:a$

$\mathrm{If}\:a>0\:\mathrm{the\:range\:is}\:f\left(x\right)\ge \:y_v$

$a=1,\:\mathrm{Vertex}\:\left(x_v,\:y_v\right)=\left(0,\:0\right)$

$f\left(x\right)\ge \:0$

Thus,

$\mathrm{Range\:of\:}x^2:\quad \begin{bmatrix}\mathrm{Solution:}\:&\:f\left(x\right)\ge \:0\:\\ \:\mathrm{Interval\:Notation:}&\:[0,\:\infty \:)\end{bmatrix}$

The graph is also attached below.

5 0

2 years ago

How many times dose 12 go into 41

jonny [76]

Answer:

3.42

Step-by-step explanation:

41/12 is 3.42

3 0

2 years ago

Read 2 more answers

PLEASE HELP IM TIMED I'LL GIVE 45 POINTS!!!!!

aksik [14]

Answer:

Jayce should not use either option. Option 1 is likely to be based so that paperbacks are overrepresented, while Option 2 is likely to be biased so that e-books are overrepresented.

Step-by-step explanation:

Given:

Jayce volunteers for the local library. The librarian wants to find out whether the patrons prefer paperback books or e-books. Jayce cannot decide which method to use for polling the patrons.

Option 1: Poll every fifth patron who enters the library on Paperback Lovers Day.

Option 2: Poll every third patron who enters the library on Technology Appreciation Day.

Since, Option 1: Poll every fifth patron who enters the library on Paperback Lovers Day. It biased because since it paperback lovers day thus, it would be likely that most people like the paperback which make it biased.

Since, Option 2: Poll every third patron who enters the library on Technology Appreciation Day. It biased because since it technology appreciation day thus, it would be likely that most people don't care about these stuff since people coming in are for technology appreciation.

Therefore, the answer is:

Jayce should not use either option. Option 1 is likely to be based so that paperbacks are overrepresented, while Option 2 is likely to be biased so that e-books are overrepresented.

Kavinsky

3 0

1 year ago

PLZ HURRY carrie is 3 times as old as Eva. in 15 years Carrie will be twice as old as Eva. how old are they both now

astraxan [27]

Answer:

Age of Eva = 15 Years

Age of Carrie = 45 Years

Step-by-step explanation:

Let the age of Eva be X years

Given that Carrie is 3 times as old as Eva

Therefore age of Carrie = 3X YEARS.

__________________________________________________________

After 15 years

Age of Eva = X + 15

Age of Carrie = 3X +15

Given that Carrie is twice as old as Eva

so according to this condition

age of Carrie = 2*Age of Eva

Substituting the age of Eva and Carrie

3X +15 = 2*(X + 15 )

=> 3X +15 = 2X +30

=> 3X - 2X = 30 - 15

=> X = 15

Since X was assumed age of Eva so age of Eva is 15 years

age of Carrie = 3X years = 3*15 = 45 years.

4 0

3 years ago

A couple intends to have two children, and suppose that approximately 52% of births are male and 48% are female.

Pachacha [2.7K]

a) Probability of both being males is 27%

b) Probability of both being females is 23%

c) Probability of having exactly one male and one female is 50%

Step-by-step explanation:

a)

The probability that the birth is a male can be written as

$p(m) = 0.52$ (which corresponds to 52%)

While the probability that the birth is a female can be written as

$p(f) = 0.48$ (which corresponds to 48%)

Here we want to calculate the probability that over 2 births, both are male. Since the two births are two independent events (the probability of the 2nd to be a male does not depend on the fact that the 1st one is a male), then the probability of both being males is given by the product of the individual probabilities:

$p(mm)=p(m)\cdot p(m)$

And substituting, we find

$p(mm)=0.52\cdot 0.52 = 0.27$

So, 27%.

b)

In this case, we want to find the probability that both children are female, so the probability

$p(ff)$

As in the previous case, the probability of the 2nd child to be a female is independent from whether the 1st one is a male or a female: therefore, we can apply the rule for independent events, and this means that the probability that both children are females is the product of the individual probability of a child being a female:

$p(ff)=p(f)\cdot p(f)$