3 years ago

Carol rolled a dice 150 times she rolled a six 39 time

Mathematics

2 answers:

Alik [6]3 years ago

8 0

Answer:

nice

Step-by-step explanation:

whats the rest of the problem or is it just that she rolled a dice

xenn [34]3 years ago

6 0

Answer:

So whats the question?

Step-by-step explanation:

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The sum of the first and third of three consecutive even integers is 136. find the three even integers.

tatyana61 [14]

Based on your problem, you only have one given. So, you can't make an equation for this because there are not limits to the equation. The only thing that you know is that the three numbers are consecutive even integers. My way of solution for this is trial-and-error. However, it's really quite easy.

For example: 42 + 46 = 88. I have to increase the numbers more to reach 136. Suppose: 82 + 86 = 168. That exceeded 136. So, it must be between 46 and 82. Suppose again: 66 + 70 = 136. Therefore, the sequence of the consecutive even integers are 66, 68, and 70.

5 0

4 years ago

Select the correct answer from each drop-down menu. Ben is making a chart in which he is listing the masses of different planeta

tia_tia [17]

Answer:

pandora is

2.20E17

Step-by-step explanation:

just did it

7 0

3 years ago

I solved some of it but now I don't know if you continue it correctly ... To be performed: (lesson: Raducali of order "n")

nikitadnepr [17]

Answer:

-9

Step-by-step explanation:

$( \sqrt[4]{7} + 2)( \sqrt[4]{7} - 2)( \sqrt{7} + 4) \\ = ( { \sqrt[4]{7} }^{2} - {{2} }^{2} )( \sqrt{7} + 4) [because (a+b)(a-b) = a² - b²]\\ = ( \sqrt{7} - 4)( \sqrt{7} + 4) \\ = { \sqrt{7} }^{2} - {4}^{2}[because (a+b)(a-b) = a² - b²] \\ = 7 - 16 \\ = - 9$