Answer:
D. 3
Step-by-step explanation:
48x=8
x=6
18/6=3
Answer:
Company balance$2,170
Service fees: $(67)
NSF check: $(170)
Note received: 1,100
Interest earned: 17
Reconciled company balance: $3,050
Step-by-step explanation:
Answer: (-3,-1)
Step-by-step explanation:
Answer:
f(x)=5000(1+0.05)^x
Step-by-step explanation:
Use the formula: f(x)=P(1+b)^x
P is principal or y-intercept. 5000 is principal.
b is the percentage in decimal form. 0.05 is b.
x is time, in this case years. Since there is not a certain number of years leave x as x.
f(x)=5000(1+0.05)^x
Hope this helps!
If not, I am sorry.
Complete question :
The denarius was a unit of currency in ancient Rome. Suppose it costs the Roman government 10 denarius per day to support 3 legionaries and 3archers. It only costs 3 denarius per day to support one legionary and one archer. Use a system of linear equations in two variables. Can we solve for a unique cost for each soldier?
Answer:
No unique solution
Step-by-step explanation:
Given that:
Cost of supporting 3 legion aries and 3 archers = 10 denarius daily
Cost of supporting one legionary and one archer = 3 denarius
Let:
Legionaries = l ; archers = a
Equation for the first sentence :
3l + 3a = 10 - - - (1)
Second sentence :
l + a = 3 - - - - - (2)
From (2)
l = 3 - a
Substituting l = 3 - a into (1)
3(3 - a) + 3a = 10
9 - 3a + 3a = 10
9 - 0 = 10
The variable cancels out, Hence, ( there is no unique solution to find the cost of each soldier)