SOLUTION
We have been given the equation of the decay as
So we are looking for the time
Plugging the values into the equation, we have
Taking Ln of both sides, we have
Hence the answer is 4308 to the nearest year
Answer:
The total area:
12 units²
Step-by-step explanation:
There are three parts on this shape:
1 big right triangle
1 rectangle
1 small right triangle
area = (4*4)/2 = 16/2 = 8units²
area = 2*1 = 2units²
area = (2*2)/2 = 2units²
8+2+2 = 12 units²
Answer:
x = y = 22
Step-by-step explanation:
It would help to know your math course. Do you know any calculus? I'll assume not.
Equations
x + y = 44
Max = xy
Solution
y = 44 - x
Max = x (44 - x) Remove the brackets
Max = 44x - x^2 Use the distributive property to take out - 1 on the right.
Max = - (x^2 - 44x ) Complete the square inside the brackets.
Max = - (x^2 - 44x + (44/2)^2 ) + (44 / 2)^2 . You have to understand this step. What you have done is taken 1/2 the x term and squared it. You are trying to complete the square. You must compensate by adding that amount on the end of the equation. You add because of that minus sign outside the brackets. The number inside will be minus when the brackets are removed.
Max = -(x - 22)^2 + 484
The maximum occurs when x = 22. That's because - (x - 22) becomes 0.
If it is not zero it will be minus and that will subtract from 484
x + y = 44
xy = 484
When you solve this, you find that x = y = 22 If you need more detail, let me know.
The answer is 2
Step-by-step explanation: 100% is the highest score you can have . then you have to divide 25 by 100 because 25 is the total amount of questions ,you should get 4,wich means each question is worth 4 points.
18 correct is a score of 72
20 correct is a score of 80
4x2=8 wich you need 8 more to get to 80 from 72
feel free to ask for more help :)
Stop posting on here and do the work yourself I usually don't mind helping people but in some cases, I need to just say do it by yourself look at notes look up the answer there are a million things you can do instead of spam posting all your questions good day
